Answer:
Step-by-step explanation:
To solve this problem you need the function
h(t) = -16t2 + v0t + h0
where t = time
v0 is the initial velocity, which in our case is 0
h0 = initial height, which in our case is 256
h(t) = 0 since we want to know when the ball will hit the ground.
0 = -16 t2 + 256
And we can solve for t
If we rearrange the terms we see that this is a difference of 2 squares
0 = 256 - 16t2
0 = (16-4t)(16+4t)
Setting each factor = 0
16-4t=0 16+4t=4
t = 4 t = -4
The second solution is discarded as time cannot be negative.
So the ball will hit the ground in 4 seconds.
Answer:velocity=185 m/s
Step-by-step explanation:
So make k the subject of the formula by divide both by sqrt(x)
h= k × sqrt(x)
k=h/sqrt(x)
k=256 / sqrt(256)
k=256 / 16
k=16
So now substitute the value of k :
h= 16 × sqrt (x)
Then differentiate:
=(1/2 × sqrt(x))× 16
=16/(2×sqrt(x)
=8/sqrt(x)
Then
= 8/sqrt(x) × 370
=8/ sqrt(256) × 370
=8/16 × 370
velocity=185 m/s
Answer:
-29a-6b+59c
Step-by-step explanation:
Answer:
I was able to do 6-8 but 9 I got stumped on as well.
Step-by-step explanation: