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Vinvika [58]
3 years ago
10

The expression below is a sum of cubes. 125x3 + 169

Mathematics
2 answers:
diamong [38]3 years ago
7 0
125x^3 = (5x)^3
125x^3 is the cube of 5x.

169 = 13^2
169 is the square of 13, but not the cube of a rational number.

The statement is false.

Drupady [299]3 years ago
7 0

Answer:

\text{The expression }125x^3+169\text{ is not the sum of cube}

Step-by-step explanation:

Given the expression

125x^3+169

we have to tell the above expression is the sum of cube

The sum of cube is of the form

a^3+b^3   →  (1)

Expression: 125x^3+169

125 is the cube of 5 and 169 is the square of 13

125x^3+169

(5x)^3+13^2

Comparing above with equation (1), we see the given expression is not the sum of cube

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In a trapezoid the lengths of bases are 11 and 18. The lengths of legs are 3 and 7. The extensions of the legs meet at some poin
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Answer:  7\frac{5}{7} unit and 18 unit

Step-by-step explanation:

Let ABCD is a trapezoid where AB and CD are the bases. ( In which AB is greatest base which shown in below figure)

AD and BC are the legs of the trapezoid ABCD.

Now, we have ( According to the question ),

AB = 18 unit, BC = 7 unit, AD = 3 unit and DC = 11 unit.

Here the leg AD extends from point D.

Similarly leg BC extends from point C.

Let they meet at point P ( shown in below diagram)

Since In triangles PAB and PDC,

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\frac{PD}{PD+3} = \frac{11}{18} ( because PA = PD+DA)

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\frac{PC}{PB} = \frac{DC}{AB}

\frac{PC}{PC+7} = \frac{11}{18} ( because PB = PC + CB)

⇒ 18 PC = 11 PD +77

⇒7PC = 77

⇒ PC = 11

Thus, PA =  PD+DA = 33/7 + 3 = 7\frac{5}{7}

And, PB = PC + CB = 11 + 7 = 18


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