All categories

3 years ago

How can “induced fit” influence the specificity of an enzyme?

1 answer:

8 0

The active site of the enzyme will change shape to make a better fit with only the appropriate substrate, which can bring the reactive portion of the enzyme closer to the substrate.

You might be interested in

What controversies can occur with using the ocean for food?

Vikki [24]

Answer: The ocean is one of Earth's most valuable natural resources. It provides food in the form of fish and shellfish about 200 billion pounds are caught each year. It's used for transportation both travel and shipping. It provides a treasured source of recreation for humans

Explanation:

7 0

3 years ago

Which of the following is an example of adhesion in organisms

12345 [234]

Adhesion is defined as a component of water , an attraction that occurs between two different substances like water and the cell walls of plant cells.

For instance:

A tree requires to be able to transport water from the roots to the leaves atop the tree over a long distance. The Water molecules will stick to the xylem in the method called as adhesion.

4 0

3 years ago

Which one is NOT one of the properties of water?

marysya [2.9K]

Answer:

a. the frozen form is more dense than the liquid form

Explanation:

The remaining properties are exhibited by water and are described as follows.

b. the frozen form is less dense than the liquid form

1. Water freezes to form ice.

2. When ice is put in water, ice starts floating in water and is visible.

3. If the density of ice was greater than water, ice would have got sunk and go downwards in the water body.

4. Hence, ice which is frozen form of water, has less density than water.

c. water is a solvent

1. The solvency is defined as the ability of a liquid to dissolve a substance.

2. Water is called the universal solvent. This means water can dissolve almost all types of substances.

3. Water is a polar solvent. The polar water molecules have the ability to break down both ionic and covalent bonds.

d. water has a high heat capacity

1. This is defined as the amount of heat needed by 1 gram of a substance so that its temperature is changed by 1 degree centigrade. The heat can either be gained or lost for the temperature to change.

2. The heat required by 1 gram of water to either increase or decrease the temperature of water is called the heat capacity of water.

e. water has a high heat of evaporation

1. This is defined as the amount of heat needed by 1 gram of a substance so that it changes its state from liquid to gas.

2. The heat required to convert 1 gram of water into vapours is called the heat of evaporation of water.

3. 1 g of water when heated at 25 centigrade needs 580 calories of heat to convert into gas.

All the above properties of water show the importance of water for life.

7 0

3 years ago

Although viruses are nonliving,

svlad2 [7]

Answer: B

Explanation:

They inject their DNA into the cell, which reprograms that cell to become that virus. This is why viruses are so deadly and can spread throughout the body and to others easily, and efficiently.

7 0

3 years ago

Assume that you have 1 mL of a solution of amylase (an enzyme) at a concentration of 15 mg protein/mL. Calculate the volume of d

lidiya [134]

Answer:

42,5 mL

Explanation:

We need to use the serial dilution formula beacuse we start with a stock concentrate solution and we need to prepare a new less concentrated one.

$DF=\frac{Vi}{Vf}$

<u>DF in the dilution factor, Vi is the initial volume and Vf is the final volume.</u>

The first step is to have the same measurment unit so we need to convert 345 µg to mg.

we know that 1 µg equals 0,001 g, hence:

$345 µg = 0,345 mg$

now the final volume is 0,345 mg protein/ mL and the inital volume is 15mg protein/mL, both of them are in the same unit so we can use the formula

$DF= \frac{15mg protein/mL}{0.345mg protein/mL}$

$DF= 43,5 mg protein/ mL$

Now since the question said that we already have 1.0mL of the amylase stock solution we need to subtract that 1.0mL to the 43,5 mg protein/mL

$43,5mL-1,0mL = 42,5 mL$

So, we need 42,5 mL of diluting buffer if we want a final concentration of 345 µg protein/mL (0.345 mg protein/mL)

8 0

3 years ago