Answer: OPTION C
Step-by-step explanation:
There are some transformations for a function f(x). Some of them are shown below:
1. If
, the function is shifted up "k" units.
2. If
, the function is shifted down "k" units.
3. If
, the function is shifted left "k" units.
4. If
, the function is shifted right "k" units.
In this case you know that the function "g" is the transformation of the function "f".
Observe that the function "f" intersects the y-axis at:

And the function "g" intersects the y-axis at:

Therefore, since both functions are 4 units apart, you can conclude that the function "f" was shifted down 4 units to get the function "g".
Then, the rule that shows that transformation is:

Answer:
Step-by-step explanation:
Parameterize the ellipse as (acos∙,bsin∙). Take points P:=(acosp,bsinp) and Q:=(acosq,bsinq) on the ellipse, with midpoint M:=(P+Q)/2.
If |PQ|=2k, then
a2(cosp−cosq)2+b2(sinp−sinq)2=4k2
The coordinates of M are
xy==a2(cosp+cosq)b2(sinp+sinq)