Answer:
there is three parts to this answer
Step-by-step explanation:
this first part is
A= 2.5
B= 49 feet
and finally
C= 0.75 seconds
Area of the front and back faces = 2 [ (8.1 x 8.1) + (1/2 x 8.1 x 2.1 ] = 148.23 in²
Area of the right and left faces = 2 [ 11.8 x 8.1 ] = 191.16 in²
Area of the top = 2 [4.6 x 11.8] = 108.56 in²
Total Area = 148.23 in² + 191.16 in² + 108.56 in² = 447.95 in²
Answer: Theo will need to paint about 447.95 in².
I set it in a big problem. Since you know that all the angles of a triable add up to 180,
m<a + m<b + m<c = 180, plug in equations/values
(36) + (3x+12) + (3x+18) = 180, subtract 36
3x+12 + 3x+18 = 144, combine like terms,
6x+30 = 144, subtract 30,
6x=114, divide by 6,
x=19. Plug in X to the equations for m<b and m<c
37.50 rounded to the nearest tenth is 37.5