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krek1111 [17]
3 years ago
11

the perimeter of a rectangular poster is 156inches its width is 36 inches and find the length and area

Mathematics
1 answer:
GenaCL600 [577]3 years ago
6 0
The length equals 42 inches because you take 36+36 because there are two widths and that equals 72. Then take 156-72 which equals 84. Take 84 divided by two because there are two lengths and you get 42 inches!
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A rectangular park is 5/6 miles wide and 1. 5/6 miles long what is the area of the park enter your anwer as a mixed number in si
valina [46]

Answer: 1 19/36

multiply 5/6 by 1 5/6

6 0
3 years ago
Sam takes x minutes yo walk from home to library and 5 minutes more to walk from the library to school than fron home to the lib
LuckyWell [14K]

Answer:

2x+5\ minutes

Step-by-step explanation:

Given:

Sam takes x minutes yo walk from home to library.

And takes 5 minutes more to walk from the library to school than from home to the library.

Express the total time taken for Sam to walk from home to school via the library in terms of x.

<u>Solution:</u>

Time taken by Sam to walk from home to library = x\ minutes

Time taken by Sam to walk from library to school = x+5\ minutes

Total time taken by Sam to walk from home to school via the library = Time taken to walk from home to library + Time taken to walk from library to school

Total time taken = x+x+5=2x+5

Therefore, the total time taken for Sam to walk from home to school via the library is 2x+5\ minutes

8 0
3 years ago
Tyler ate x fruit snacks, Han ate 3/4 less than that. Write an equation to represent the relationship between the number Tyler a
Citrus2011 [14]

Answer:

0.75x = y

or

1/4 = y

4 0
3 years ago
If a test of H subscript 0 colon space mu subscript D equals 0 space v s. space H subscript a colon space space mu subscript D g
lara [203]

Answer:

p_v =P(t_{(n-1)}>t_{calculated}) =0.0601

The p value on this case is given  by the problem.

If we compare the p value with a significance level assumed \alpha=0.05, we see that p_v > \alpha and we can conclude that we FAIL to reject the null hypothesis that the difference mean between after and before is less or equal than 0.

Step-by-step explanation:

A paired t-test is used to compare two population means where you have two samples in  which observations in one sample can be paired with observations in the other sample. For example  if we have Before-and-after observations (This problem) we can use it.  

Let put some notation  

x=test value before , y = test value after

The system of hypothesis for this case are:

Null hypothesis: \mu_y- \mu_x \leq 0

Alternative hypothesis: \mu_y -\mu_x >0

The first step is calculate the difference d_i=y_i-x_i

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}

The 4 step is calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=t_{calculated}

The next step is calculate the degrees of freedom given by:

df=n-1

Now we can calculate the p value, since we have a right tailed test the p value is given by:

p_v =P(t_{(n-1)}>t_{calculated}) =0.0601

The p value on this case is given  by the problem.

If we compare the p value with a significance level assumed \alpha=0.05, we see that p_v > \alpha and we can conclude that we FAIL to reject the null hypothesis that the difference mean between after and before is less or equal than 0.

4 0
3 years ago
What is the sum of the first eight terms of the series?
Ray Of Light [21]
Observe that as the series progresses, the term decreases by 1/4. To show this, observe the first four terms of the series below.

-200 = (1/4)(-800)
-50 = (1/4)(-200)
-12.5 = (1/4)(-50)

Since we have a common ratio, r, of 1/4, we can use the properties of a geometric series to find the 8th term of the series.

Recall that to find the sum of the nth term of a geometric series, we have

S_{n} = a(\frac{1-r^{n}}{1-r})

where a is the first term of the series and r is the ratio.

So, for the first eight terms, we have

S_{8} = -800(\frac{1-(\frac{1}{4})^8}{1- \frac{1}{4}})
S_{8} \approx -1066.65

Therefore, the sum of the 8th series is approximately -1066.65. 

Answer: -1066.65
3 0
3 years ago
Read 2 more answers
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