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geniusboy [140]
3 years ago
6

What are all of the real roots of the following polynomial? f(x) = x4 - 24x2 - 25

Mathematics
2 answers:
MrMuchimi3 years ago
5 0
It factors as ...
  f(x) = (x² -25)(x² +1) = (x -5)(x +5)(x² +1)
A root will make one of the factors equal to zero. The quadratic factor has only complex roots.

The real roots are x = ±5.

AfilCa [17]3 years ago
4 0

Answer:

5, -5

Step-by-step explanation:

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Write the polynomial in factored form. <br><br> p(x)=(x+5)(x-___)(x+___)
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Answer:


Step-by-step explanation:

Given : p(x)=x^{3} +6x^{2} -7x-60

Solution :

Part A:

First find the potential roots of p(x) using rational root theorem;

So, \text{Possible roots} =\pm\frac{\text{factors of constant term}}{\text{factors of leading coefficient}}

Since constant term = -60

Leading coefficient = 1

\text{Possible roots} =\pm\frac{\text{factors of 60}}{\text{factors of 1}}

\text{Possible roots} =\pm\frac{1,2,3,4,5,6,10,12,15,20,60}{1}

Thus the possible roots are  \pm1, \pm2, \pm 3, \pm4, \pm5,\pm6, \pm10, \pm12, \pm15, \pm20, \pm60

Thus from the given options the correct answers are -10,-5,3,15

Now For Part B we will use synthetic division

Out of the possible roots we will use the root which gives remainder 0 in synthetic division :

Since we can see in the figure With -5 we are getting 0 remainder.

Refer the attached figure

We have completed the table and have obtained the following resulting coefficients: 1 , 1,−12,0.  All the coefficients except the last one are the coefficients of the quotient, the last coefficient is the remainder.

Thus the quotient is x^{2} +x-12

And remainder is 0 .

So to get the other two factors of the given polynomial we will solve the quotient by middle term splitting

x^{2} +x-12=0

x^{2} +4x-3x-12=0

x(x+4)-3(x+4)=0

(x-3)(x+4)=0

Thus x-3 and x+4 are the other two factors

So , p(x)=(x+5)(x-3)(x+4)





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475x + 90

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475x + 90 ≤ 1200

475x ≤ 1200 - 90

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