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Sonja [21]
3 years ago
11

What’s the answer to this

Mathematics
2 answers:
Alchen [17]3 years ago
6 0

Answer:

B

Step-by-step explanation:

I solved in the picture

Hope this helps ^-^

stepan [7]3 years ago
5 0

Answer:X=2, and -36

Step-by-step explanation:

Ehh

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What is the first integer to the right of 0 on the number line
Nesterboy [21]

Answer:

1

Step-by-step explanation:

Numbers to the "right of 0" implies the positive numbers.  And an integer has no fractional component.  Thus, the first integer to the right of 0 would be 1.

Cheers.

4 0
3 years ago
The sum of a number and 4.7 is 8.1.
Sloan [31]

<em>Greetings from Brasil...</em>

Be that unknown number X

Then we can write the following expression:

X + 4.7 = 8.1

<h2>X = 3.4</h2>

5 0
3 years ago
Sorry if the image is blurry
klemol [59]

Answer:

I believe x is greater than or equal to 1

8 0
3 years ago
What is 2 1/2 /1/3 ?
DanielleElmas [232]

Answer:

15/2

Step-by-step explanation:

My interpretation of your math expression is "2  1/2 divided by 1/3."

I prefer to write this as:

 5        1

----- ÷ -----

 2         3

which is equivalent to:

 5        3

----- * ----- = 15/2

 2        1

5 0
3 years ago
A network provider investigates the load of its network. The number of concurrent users is recorded at fifty locations (thousand
beks73 [17]

Answer:

see explaination

Step-by-step explanation:

Using the formulla that

sum of terms number of terms sample mean -

Gives the sample mean as \mu=17.954

Now varaince is given by

s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97

and the standard deviation is s=\sqrt{9.97}=3.16

b) The standard error is given by

\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45

c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1

Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88

d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05

Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96

or a number which is less than 15.83-1.5(4.05)=9.76

As there is no such number so the given sample has no outliers

5 0
3 years ago
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