Answer:
a) Option D is correct for this question.
That is, A or B is the event that the person is overweight or obese.
But for other questions whose sets aren't disjoint, event A or B usually means all the elements that are in either A or B or both sets.
b) Option C.
P(A or B) = 0.71
c) Option A
P(C) = 1 - P(A or B) = 0.29
Step-by-step explanation:
b) Event B specifically rules out obesity, meaning, set A and set B have no elements in common.
In a normal probability question, event A or B usually means all the elements that are in either A or B and elements that are in the two sets.
But for this question, since, it has been made clear that there are no common elements in the two sets, event A or B is event that the person is overweight or obese. Option D.
b) For disjoint sets, P(A or B) = P(A) + P(B) = 0.38 + 0.33 = 0.71. Option C.
c) P(C) is the set of all elements that are not in either A or B.
P(C) = 1 - P(A or B) = 1 - 0.71 = 0.29. Option A.
