The equation for speed is s=d/t, s=276/6.5. Then, you divide 276 in 6.5: s is approximately 42 miles/hour. So, he drove 12 miles/hour faster getting there than coming back home.
Answer:
The correct option is (C).
Step-by-step explanation:
According to the Central Limit Theorem if we have n unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.
Then, the mean of the distribution of sample means is given by,
And the standard deviation of the distribution of sample means is given by,
The information provided is:
<em>μ</em> = 3.5
<em>σ</em> = 1.7078
<em>n</em> = 400 = number of times the experiment is repeated.
As the sample size is quite large, i.e. <em>n</em> = 400 > 30 the central limit theorem can be used to approximate the sampling distribution of the sample mean.
The mean of the distribution of sample means is:
The standard deviation of the distribution of sample mean is:
The distribution of the sample mean is:
.
Thus, the correct option is (C).
Answer:
Step-by-step explanation:
All she needs to know is that a reflection across the x-axis is when the x coordinate stays the same and the y-coordinates change.
Hope this helped.
1. Proof
1. Proofln(x) dx. set. u = ln(x), dv = dx. then we find. du = (1/x) dx, v = x.
1. Proofln(x) dx. set. u = ln(x), dv = dx. then we find. du = (1/x) dx, v = x.substitute. ln(x) dx = u dv.
1. Proofln(x) dx. set. u = ln(x), dv = dx. then we find. du = (1/x) dx, v = x.substitute. ln(x) dx = u dv.and use integration by parts. = uv - v du.
1. Proofln(x) dx. set. u = ln(x), dv = dx. then we find. du = (1/x) dx, v = x.substitute. ln(x) dx = u dv.and use integration by parts. = uv - v du.substitute u=ln(x), v=x, and du=(1/x)dx.
hope this will help u
I’m pretty sure this prom or will always equal error but I do not know yet I will keep trying and get back to you if I find it