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Firlakuza [10]
3 years ago
5

Find the ninth term of the sequence sqrt 5, sqrt 10, ^2sqrt 5

Mathematics
1 answer:
hjlf3 years ago
5 0
The rule of geometric sequence is   ⇒⇒⇒ a * r^(n-1)
Where a is the first term and  r is the common ratio
for the given sequence  √5 , √10 , 2√5 , .......
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5

the correct answer is the third option 16√5
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