We are given the area of the region under the curve of the function f(x) = 5x + 7 with an interval [1, b] which is 88 square units where b > 1
We need to find the integral of the function f(x) = 5x + 7 with the limits 1 and b
5/2 x^2 + 7x (limits: 1, b)
substitute the limits:
5/2 (1^2) + 7 (1) - 5/2 b^2 + 7b = 0
solve for b
Then after solving for b, this would be your interval input with 1: [1, b].<span />
Yes. 95 is correct.
You have three congruent "indentations" in the right hand side. Thus each section must be 15/3 = 5 cm long.
The top rectangle will be 8*5 = 40 cm^2
The bottom rectangle will also be 8*5 = 40 cm^2
The middle area will be 5(8-5) = 5 * 3 = 15 cm^2
40 + 40 + 15 = 95
The range is how long the graph extends vertically. So, the lowest value is -9 (since the graph extends down until -9) and the highest value is 9 (since the graph extends up until 9). The lowest value goes in the first box and the highest value goes in the second box. The range is:
-9 ≤ <em>g</em>(<em>t </em>) ≤9
Answer:
Its Option C
Step-by-step explanation:
The difference is 180 - 135 = $45
So it is 45 * 100 / 135
= 33.33% greater
