Select the correct answer. Ria is an Indian student who was admitted to a US university. Her annual tuition is $42,000. She has
2 answers:
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In this question , we have to write an arithmetic expression that calculates the average of 18 and 46.
TO find the average, we have to add the numbers and divide by 2.
So here we have to add 18 and 46 and divide by 2, that is
And that's the required algebraic expression .
Answer:
A 98% confidence interval for the mean assembly time is [21.34, 26.49] .
Step-by-step explanation:
We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.
Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;
P.Q. = ~
where, = sample average time = 23.92 minutes
s = sample standard deviation = 6.72 minutes
n = sample of times = 40
= population mean assembly time
<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>
<u>So, a 98% confidence interval for the population mean, </u><u> is;
</u>
P(-2.426 < < 2.426) = 0.98 {As the critical value of z at 1% level
of significance are -2.426 & 2.426}
P(-2.426 < < 2.426) = 0.98
P( <
<
) = 0.98
P( <
<
) = 0.98
<u>98% confidence interval for</u> = [
,
]
= [ ,
]
= [21.34, 26.49]
Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .