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3 years ago

308 students went on a field trip. Ten buses were filled and 8 students traveled in cars. How many students were in each bus ?

Mathematics

2 answers:

jolli1 [7]3 years ago

7 0

Answer:

30 students per bus

Step-by-step explanation:

308-8=300

300 students/10 buses

=30 students per bus

Irina-Kira [14]3 years ago

7 0

Answer:

30 students

Step-by-step explanation:

30 students were in each bus because there are 308 students and if you subtract the 8 that went in the cars you get 30. 30 times 10 is 300.

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Solve each system by substitution<br><br> 2x - 3y = -1<br> X + 4y = -6

lord [1]

Answer:

(- 2, - 1 )

Step-by-step explanation:

Given the 2 equations

2x - 3y = - 1 → (1)

x + 4y = - 6 → (2)

Rearrange (2) expressing x in terms of y by subtracting 4y from both sides

x = - 6 - 4y → (3)

Substitute x = - 6 - 4y into (1)

2(- 6 - 4y) - 3y = - 1 ← distribute and simplify left side

- 12 - 8y - 3y = - 1

- 12 - 11y = - 1 ( add 12 to both sides )

- 11y = 11 ( divide both sides by - 11 )

y = - 1

Substitute y = - 1 into (3) for corresponding value of x

x = - 6 - 4(- 1) = - 6 + 4 = - 2

Solution is (- 2, - 1 )

3 0

3 years ago

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forsale [732]

Answer:

Step-by-step explanation:

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8 0

3 years ago

If x-1/x=5 find x^3+1/x^3=?

ipn [44]

$\dfrac{x-1}{x}=5\ \ \ \ /x\neq0\\\\\dfrac{x-1}{x}=\dfrac{5}{1}\ \ \ \ |\text{cross multiply}\\\\5x=x-1\ \ \ \ |-x\\\\5x=1\ \ \ \ |:5\\\\x=0.2\\\\\dfrac{x^3+1}{x^3}=\dfrac{x^3}{x^3}+\dfrac{1}{x^3}=1+\dfrac{1}{x^3}\to1+\dfrac{1}{0.2^3}=1+\dfrac{1}{0.008}\\\\=1+\dfrac{1}{\frac{8}{1,000}}=1+\dfrac{1,000}{8}=1+125=126\\\\\text{Answer:}\ \dfrac{x^3+1}{x^3}=126$

5 0

3 years ago

Read 2 more answers

What is the answer to this question

timama [110]

Answer:

$b^6z^612a^5$

Step-by-step explanation:

The first step is to combine like terms, and multiply them together first. Since multiplication is commutative, it doesn't matter in what order you do it. Therefore, this can be rewritten as $(2a^2\cdot 6a^3)\cdot(b^4\cdot b^2)\cdot(z\cdot z^5)=(12a^5)\cdot(b^6)\cdot(z^6)=b^6z^612a^5$ . Hope this helps!