Answer: There are 65 different ways Roberto can display his figures.
Step-by-step explanation:
Since we have given that
Number of sports cards in an album = 18
Number of cards some pages hold =2
Number of cards some other pages hold=3
Now, there are 4 cases to generate this shown as follow:
Case I:
If we consider 6 cards of 3 pages then it will make
![3\times 6=18\ cards](https://tex.z-dn.net/?f=3%5Ctimes%206%3D18%5C%20cards)
So, there is no cards of 2 pages .
So, different ways in this case will be
![^6C_6=1](https://tex.z-dn.net/?f=%5E6C_6%3D1)
Case II:
If we consider 3 cards of 2 pages and 4 cards of 3 pages , then it will again becomes
So, different ways in this case is
![\frac{7!}{3!\times 4!}=35](https://tex.z-dn.net/?f=%5Cfrac%7B7%21%7D%7B3%21%5Ctimes%204%21%7D%3D35)
Case III:
If we consider 6 cards of 2 pages and 2 cards of 3 pages then it will become
![6\times 2+2\times 3=12+6=18](https://tex.z-dn.net/?f=6%5Ctimes%202%2B2%5Ctimes%203%3D12%2B6%3D18)
So, different ways in this case is
![\frac{8!}{6!\times 2!}=28](https://tex.z-dn.net/?f=%5Cfrac%7B8%21%7D%7B6%21%5Ctimes%202%21%7D%3D28)
Case IV:
if we consider 9 cards of 2 pages then it will alone makes it
there is no card of 3 pages,
So, different ways in this case is
![^9C_9=1](https://tex.z-dn.net/?f=%5E9C_9%3D1)
So, total number of ways Robert can display his figures is
![1+35+28+1=65](https://tex.z-dn.net/?f=1%2B35%2B28%2B1%3D65)
Hence, there are 65 ways to do so.