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san4es73 [151]
3 years ago
15

Write in standard form 8x2−5+7x4−9x−x5 Please explain i don't understand

Mathematics
2 answers:
allochka39001 [22]3 years ago
8 0
This is the standard form of your question.

FinnZ [79.3K]3 years ago
7 0
-x^5+7x^4+8x^2-9x-5.....
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cos x = 0.5

Step-by-step explanation:

cot x  = (cos x) / (sin x)

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cos x = 0.5

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if someone goes in the northeast quadrant, then goes to the southeast quadrant, in what general direction should they head
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I'm genuinely lost in any problems like this and my teachers are no help, I need help doing exponents in general, everything to
Stolb23 [73]

Answer:

See below.

Step-by-step explanation:

4)

So we have the expression:

(-6n^{-3})^2

We can use the power of a product property, where:

(ab)^n=a^n\cdot b^n

So:

=(-6)^2\cdot(n^{-3})^2

For the left, -6 squared is the same as -6 times -6. This equals positive 36.

For the right, we can use the power of a power property. The property says that:

(a^n)^k=a^{nk}

So:

(n^{-3})^2=n^{(-3)(2)}\\=n^{-6}

So, all together, we have:

=(-6)^2\cdot(n^{-3})^2\\=36n^{-6}

6)

We have the expression:

-\frac{3x^0}{x^4}

First, note that anything to the zeroth power (except for 0) is 1, thus, x^0 is also 1. Simplify:

=-\frac{3}{x^4}

And that's the simplest we can do :)

Notes for 6)

We <em>can</em> put the x^4 to the numerator. Recall that when you put an exponent to opposite side, you put a negative. In other words:

x^n=\frac{1}{x^{-n}}

And vice versa:

\frac{1}{x^{-n}}=x^n

So, we can write the above as:

=-\frac{3}{x^4}\\=-\frac{3}{x^{-(-4)}}\\=-3x^{-4}

However, traditionally, we want only positive exponents, so this wouldn't be correct.

4 0
4 years ago
Read 2 more answers
what is an equation of the line that passes through the point (6, 8) and is perpendicular to a line with equation y=3/2x 5
Evgen [1.6K]

Answer:

y= -2/3x+12

Step-by-step explanation:

3 0
2 years ago
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