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Ne4ueva [31]
3 years ago
10

Mark has twice as many quarters as nickels and three more dimes than nickels. He has 4.20 in all. How many of each type of coin

does he have?
Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0

Answer:

Number of nickels = 6

number of dimes = 9

number of quarters =12

Step-by-step explanation:

Let 'q' be the number of quarters and 'n' be the number of nickels

and 'd' be the number of dimes

twice as many quarters as nickels

q=2n

three more dimes than nickels.

d=3+n

1 nickel = 5 cents

1 dime = 10 cents

1 quarter = 25 cents

4.20 dollars = 420 cents

5n+10d+25q=420

replace q  and d in the above equation

5n+10(3+n)+25(2n)=420

5n+30+10n+50n=420

65n+30=420

Subtract 30 from both sides

65n=390

divide both sides by 65

n=6

Number of nickels = 6

number of dimes = 3+n=3+6=9

number of quarters = 2n=2(6)= 12

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BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

\large \boxed{sin \theta = tan \theta cos \theta} \\  \large \boxed{tan^{2}  \theta + 1 =  {sec}^{2} \theta}

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

\large{ {4}^{2}  + 1 =  {sec}^{2} \theta } \\  \large{16 + 1 =  {sec}^{2} \theta } \\  \large{ {sec}^{2}  \theta = 17}

As we know, sec²θ = 1/cos²θ.

\large \boxed{sec \theta =   \frac{1}{cos \theta} } \\  \large \boxed{ {sec}^{2}  \theta =  \frac{1}{ {cos}^{2}  \theta} }

And thus,

\large{  {cos}^{2}  \theta =  \frac{1}{17}}   \\ \large{cos \theta =  \frac{ \sqrt{1} }{ \sqrt{17} } } \\  \large{cos \theta =  \frac{1}{ \sqrt{17} }  \longrightarrow  \frac{ \sqrt{17} }{17} }

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

\large{cos \theta =   \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta =  -  \frac{ \sqrt{17} }{17}}

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

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Answer

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