-15 is 15 below o
you are adding 4 , so you are getting closer to 0
so you would actually use subtraction, 15-4 = 11
since 15 is negative, and you are adding a number smaller than 15, the answer would be negative so it would be -11
6 sec can take penny to strike the ground.
Solution:
Given data:
feet
feet
Re-arrange the terms from greatest degree to smallest degree.
We can solve it by applying quadratic formula,
Here a = –16, b = 48, c = 288
Now, write find two t's using plus and minus operation.
t = –3 (or) t = 6
We cannot write time is negative. so neglect t = –3.
Therefore t = 6.
Hence 6 sec can take penny to strike the ground.
Only Table 2 shows direct variation. Every y value is 7 times the associated x value.
There are many systems of equation that will satisfy the requirement for Part A.
an example is y≤(1/4)x-3 and y≥(-1/2)x-6
y≥(-1/2)x-6 goes through the point (0,-6) and (-2, -5), the shaded area is above the line. all the points fall in the shaded area, but
y≤(1/4)x-3 goes through the points (0,-3) and (4,-2), the shaded area is below the line, only A and E are in the shaded area.
only A and E satisfy both inequality, in the overlapping shaded area.
Part B. to verify, put the coordinates of A (-3,-4) and E(5,-4) in both inequalities to see if they will make the inequalities true.
for y≤(1/4)x-3: -4≤(1/4)(-3)-3
-4≤-3&3/4 This is valid.
For y≥(-1/2)x-6: -4≥(-1/2)(-3)-6
-4≥-4&1/3 this is valid as well. So Yes, A satisfies both inequalities.
Do the same for point E (5,-4)
Part C: the line y<-2x+4 is a dotted line going through (0,4) and (-2,0)
the shaded area is below the line
farms A, B, and D are in this shaded area.
The longest is 4/6 of a hr and the shortest is 1/6 of a hr
Subtract -3/6 hr
