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7nadin3 [17]
4 years ago
7

How to solve for h, A=9h​

Mathematics
2 answers:
LekaFEV [45]4 years ago
8 0

Answer:

h=a/9

Step by step explanation:

A=9h

to solve for h, divide both sides by 9

A/9=9h/9

A/9=h

h=A/9

taurus [48]4 years ago
3 0

Answer:

\large\boxed{h=\dfrac{A}{9}}

Step-by-step explanation:

9h=A\qquad\text{divide both sides by 9}\\\\\dfrac{9\!\!\!\!\diagup^1h}{9\!\!\!\!\diagup_1}=\dfrac{A}{9}\\\\h=\dfrac{A}{9}

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How to find the side of a rhombus with given diagonals?
spayn [35]
The diagonals of a rhombus are perpendicular bisectors of each other. You can use the Pythagorean theorem. If the diagonals are length "a" and "b", the side length of the rhombus (s) is
  s = (1/2)√(a²+b²)
7 0
3 years ago
The number of counties in state A and the number of counties in state B are consecutive even integers whose sum is 138 138. If s
ss7ja [257]

Answer:

The number of counties in state A are 70.

The number of counties in state B are 68.

Step-by-step explanation:

The number of counties in state A and the number of counties in state B are consecutive even integers whose sum is 138.

Let the two consecutive even integers be x and x+2.

As their sum is 138, we can denote this mathematically as :

x+x+2=138

=> 2x+2=138

=> 2x=138-2

=> 2x=136

Now, we get x = 68

And x+2=68+2 = 70

Hence, the two numbers are 68 and 70.

So, the number of counties in state A are 70.

The number of counties in state B are 68.

5 0
3 years ago
Read 2 more answers
URGRENNTTT PLSS HELPP 50 POINTSS!!!!! Students were asked to simplify the expression cotangent theta plus tangent theta over cot
Naddika [18.5K]

The student that simplified the expression incorrectly is student 2

<h3>How to determine the incorrect result?</h3>

The steps are given as:

\frac{\cot(\theta) + \tan(\theta)}{\cot(\theta)}

Student 1:

  • Step 1: \frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)}
  • Step 2: 1 + \frac{\tan(\theta)}{\cot(\theta)}
  • Step 3: 1 + tan²(Ф)
  • Step 4: sec²(Ф)

Student 2:

  • Step 1: \frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)}
  • Step 2: \frac{1 +  \tan^2(\theta)}{\cot(\theta)/\tan(\theta)}
  • Step 3: sec²(Ф)/tan²(Ф)
  • Step 4: csc²(Ф)

As a general trigonometry rule;

\frac{\cot(\theta) + \tan(\theta)}{\cot(\theta)} = \sec^2(\theta)

This means that student 1 is correct, while student 2 is not

The first error in student 2's workings is in step 2, where we have:

\frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)} = \frac{1 +  \tan^2(\theta)}{\cot(\theta)/\tan(\theta)}

The above expression is not justified and cannot be proved by any trigonometry rule

Since the step 2 is incorrect, the other steps cannot be used.

Hence, the student that simplified the expression incorrectly is student 2

Read more about trigonometric expressions at:

brainly.com/question/8120556

#SPJ1

5 0
2 years ago
What is the value of C in the equation 12c - 53 = 91?
kirza4 [7]

Answer: 12

Step-by-step explanation:

C=12 because u do 91+53 =144 then 144/12=12

C=12

3 0
3 years ago
Leiff goes online to buy a new video game. He finds a site that currently has a promotion of 15% off on all orders over $50. Lei
dusya [7]

Answer:

yea what the other guy said

3 0
3 years ago
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