For Each Data Set, Determine the median, the first and third Quartiles, and the interquartile Range.

1 answer:

5 0

1. First of all arrange the data set in either ascending or descending order.
12, 19, 24, 26, 31, 38, 53. N = 7 (number of data items)
Median position = 1/2(N + 1)th item = 1/2(7 + 1)th item = 1/2(8)th item = 4th item = 26
First quatile = 1/4(N + 1)th item = 1/4(7 + 1)th item = 1/4(8)th item = 2nd item = 19
Third quatile = 3/4(N + 1)th item = 3/4(7 + 1)th item = 3/4(8)th item = 6th item = 38
Interquatile range = Third quartile - first quatile = 38 - 19 = 19

You might be interested in

If f(x) = 4x - 20, what is f(4)? O A. -4 оо O B. -12 O c. 4 O D. 16

4vir4ik [10]

Answer:

A. - 4

Step-by-step explanation:

f(4) = 4(4) - 20 = 16 - 20 = - 4

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%28-3x%5E2y%29%5E%7B4%7D" id="TexFormula1" title="(-3x^2y)^{4}" alt="(-3x^2y)^{4}" align="absm

Valentin [98]

Answer:

errr polynomials ahaha

so basically we can multiply the power outside of the parantheses with the exponents on the inside:

$-3x^{2*4} y^{1*4}$

this will give us:

-3x^8y^4

we also unfortunately, have to use the power on the coefficient -3 as well and we cant just MULTIPLY -3 by 4, we are going to have to multiply -3 with -3 4 TIMES(anytime we see a coefficient we MUST multiply the coefficient by itself according to the number outside of the parantheses)

so:

-3*-3*-3*-3=81

final expression

$81x^{8}y^{4}$