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4 years ago

Is (-2,3/4,-2/7,0) a set of real numbers

Mathematics

1 answer:

DedPeter [7]4 years ago

8 0

Answer:

Yes

Step-by-step explanation:

All of these numbers are real numbers. None of them are complex numbers or irrational like <em>i</em>, s the answer is yes.

I have provided a chart to help you out with this topic.

Hope this helps! :)

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20 + 549+ 48574 - 46567476 x 987665 +1 if a apple is a shoo wath is a ñ

kotegsom [21]

if (20 + 549+ 48574 - 46567476 x 987665) is the calculations of a number of apples, its total value is mathematically given as

X=−4.59930662*10^13

<h3>What is the number of apples?</h3>

Generally, the equation for the statement is mathematically given as

20 + 549+ 48574 - 46567476 x 987665 +1

Let's equate it to x, Therefore

X= 20 + 549+ 48574 - 46567476 x 987665 +1

Using BODMAS

X= 20 + 549+ 48574 - 4.59930662*10^13 +1

X=49143-4.59930662×10^13

X=−4.59930662×10^13

In conclusion, the number of apples

X=−4.59930662*10^13

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2 years ago

Is anyone good at this? Please help me!!

enyata [817]

Speed: 30mi/sec
Seconds in one minute: 60
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take the speed of 30miles / seconds and times it with 360, and you get a total distant traveled: 10800 miles

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3 years ago

If a $200 billion increase in investment spending creates $200 billion of new income in the first round of the multiplier proces

telo118 [61]

The multiplier would be 4, I believe so.

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3 years ago

Help me with 16,17,18,and 19 please simpl

mixas84 [53]

Answer:

Ques 16)

We have to simplify the expression:

$\dfrac{t^2}{t^2+3t-18}-(\dfrac{5t}{t^2+3t-18}-\dfrac{t-3}{t^2+3t-18})\\ \\=\dfrac{t^2}{t^2+3t-18}-(\dfrac{4t+3}{t^2+3t-18})\\ \\=\dfrac{t^2-4t-3}{t^2+3t+18}$

Ques 17)

$\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{2w^2-9w+4}{(2w^2+9w-5)(w^2-w-12)}\\ \\=\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{(2w-1)(w-4)}{(2w-1)(w+5)(w+3)(w-4)}\\\\=\dfrac{3w^2+7w-7}{(w+3)(w+5)}+\dfrac{1}{(w+3)(w+5)}\\\\=\dfrac{3w^2+7w-7+1}{(w+3)(w+5)}\\\\=\dfrac{(3w-2)(w+3)}{(w+5)(w+3)}\\\\=\dfrac{3w-2}{w+5}$

Ques 18)

Let the blank space be denoted by the quantity 'x'.

$\dfrac{x}{12a^2+8a}+\dfrac{15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\ \\\dfrac{x+15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a(3a+2)}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a}=7a\\\\x+15a^2=28a^2\\\\x=28a^2-15a^2\\\\x=13a^2$

Ques 19)

Let the missing quantity be denoted by 'x'.

$\dfrac{p^2+7p+2}{p^2+5p-14}-\dfrac{x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\ \\\dfrac{p^2+7p+2-x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\\\\dfrac{p^2+7p+2-x}{(p-2)(p+7)}=\dfrac{p-1}{p-2}\\\\p^2+7p+2-x=(p-1)(p+7)\\\\p^2+7p+2-x=p^2+6p-7\\\\x=p+9$

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3 years ago

G(-2, 5), H(6, 5), J(6, -1) 17 Find the coordinates of the centroid.

eimsori [14]

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4 years ago