Which graph represents an odd function?
2 answers:
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Answer:
(x - 6)² + (y - 2)² = 128
Step-by-step explanation:
Given as the circle has center ( 6 , 2)
and it passes through points (-2 , -6)
Now , standard equation of circle is (x -a)² + (y- b)² = r² , where (a , b) is center and r is the radius .
Again from given center the circle equation is
(x- 6)² + (y- 2)² = r²
Now this circle passes through points (-2 , -6)
so, (-2 -6)² + (-6 -2)² = r²
so, 8² + 8² = r²
Or, 128 = r²
i.e Radius pf this circle = 8
Hence the circle equation formed is
(x- 6)² +( y-2)² = 128 Answer
