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Vsevolod [243]
4 years ago
14

Which graph represents an odd function?

Mathematics
2 answers:
olga55 [171]4 years ago
7 0
The 3rd graph should be it
jeka57 [31]4 years ago
7 0

The third graph, with (-4,0),(-3,1),(-2,-3),(-1,-2),  (1,2),(2,3),(3,-1),(4,0)

We see the pattern, if we have (x,f(x)) we have (-x, -f(x)).  In other words

f(-x) = -f(x)

which is the definition of an odd function.

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valerie has 8 blue markers and 10 green markers. she has 2 times as many red markers as blue and green markers combined. which d
aleksley [76]
This question means the than (8 + 10) x 2 = red markers. She has 32 red markers, 8 blue markers, and 10 green markers. If you add them all up, you get 50 markers.
7 0
3 years ago
Help will give Brainly points
Elodia [21]

Answer:

\frac{24}{25}

Step-by-step explanation:

\cos(\theta)=\frac{\textrm{adjacent}}{\textrm{hypotenuse}}

4 0
2 years ago
Fine the sum of the series
lapo4ka [179]

Answer:

6825

Step-by-step explanation:

From the equation, the series is a geometric series, such that

a = 5

r = 4

n = 6

sum of a geometric series is a(r^n - 1)/(r - 1)

therefore,

sum of the series is 5 x (4^6 - 1) / (4 - 1)

= 5 x (4096 - 1) / 3

= 5 x 4095 / 3

= 6825

6 0
3 years ago
Twice a number (z) added to 21 is equal to 9 times the number added to 7. What is the number?
pickupchik [31]

Answer:

The number is  2

Step-by-step explanation:

Twice a number (z) = 2*z = 2z

Twice a number (z) added to 21  = 2z + 21

9 times the number added to 7 = 9z + 7

9z + 7 = 2z + 21

Subtract 2z form both sides

9z - 2z + 7 = 21

       7z + 7 = 21

Subtract 7 from both sides

7z = 21 - 7

 7z = 14

Divide both sides by 7

z = 14/7

z = 2

5 0
3 years ago
Type a digit that makes this statement true.<br><br> 5,072,<br> 00 is divisible by 8.
lina2011 [118]

The divisibility rule for 8 is that the last three digits have to be divisible by 8.

The third digit of 5072_00(from the right) could be 2, 4, 6, 8, or 0, because 200, 400, 600, 800, and 0 are divisible by 8.

Pls give brainliest.

6 0
3 years ago
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