Whisper-20dB
Quiet Residence-30dB
Soft stereo in Residence-40dB
Average Speech-60dB
Cafeteria-80dB
Pneumatic Jackhammer-90dB
Loud crowd noise-100dB
Accelerating Bike-100dB
Rock concert-120dB
Jet Engine (75 ft away)-140dB
(1)Mode=100dB (since 100 is occurring the maximum no. of times, i.e. it has the highest frequency of 2)
(2)Mean=sum of observations/Total number of observations
=(20+30+40+60+80+90+100+100+120+140)/10
=770/10=10dB
(3)Median= 1/2[{n/2}th observation + {(n/2)+1}th observation], where, n=total no. of observations
So, 1/2[{10/2}th observation + {(10/2)+1}th observation]
=1/2[5th observation+6th observation]
=1/2[80+90] [Because:5th observation=80dB and 6th=90dB]
=1/2(170)
=85
Therefore, median=85dB
Answer:
8j-k+14
8(0.25)-1+14=2-1+14=15
Step-by-step explanation:
Hello!,
First you would divide 72 by 12 which would be....6 okay 6 adults.
Second you would divide 72 by 9 witch is...... 8 kids
6 adults 8 kids
5 7/12 because 2 1/3 + 3 1/4 = 67/12 (or 5 7/12) This can be shown as: 2 4/12 + 3 3/12 = 5 7/12
