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3 years ago

Which of the following is not part of the converse of the triangle proportionality theorem?

Mathematics

2 answers:

Anestetic [448]3 years ago

6 0

Answer:

a perpendicular line to one side

Step-by-step explanation:

professor190 [17]3 years ago

3 0

Converse-if a line drawn frm one side of a triangle to the other side divides the 2 sides in equal ratio then the line is parallel to the third side.

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Eggs with defects in terms of the number of eggs they inspected as shown

mamaluj [8]

Answer:

Step-by-step explanation:

You need to draw a line of best fit, then extend the x-axis, but from inspection I think it is 23.

(19 is too low, 36 is too high)

6 0

2 years ago

Simplify the expression by combining like terms<br> 2v + 6 + 4v + 8 + v

harkovskaia [24]

7v + 14

(2v + 4v + v) + (6 + 8)

7v + 14

5 0

3 years ago

Read 2 more answers

Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id

Thepotemich [5.8K]

$\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

Explanation

$\frac{1}{a+bi}=c+di$

Step 1

multiplicate by the conjugate

$\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}$

notice that

$\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\ \end{gathered}$ $\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

I hope this helsp you

6 0

1 year ago

BRAINLIESTTT ASAP! PLEASE HELP ME :)

11Alexandr11 [23.1K]

<h3>Answer: B) Only the first equation is an identity</h3>

========================

I'm using x in place of theta. For each equation, I'm only altering the left hand side.

Part 1

cos(270+x) = sin(x)

cos(270)cos(x) - sin(270)sin(x) = sin(x)

0*cos(x) - (-1)*sin(x) = sin(x)

0 + sin(x) = sin(x)

sin(x) = sin(x) ... equation is true

Identity is confirmed

---------------------------------

Part 2

sin(270+x) = -sin(x)

sin(270)cos(x) + cos(270)sin(x) = -sin(x)

-1*cos(x) + 0*sin(x) = -sin(x)

-cos(x) = -sin(x)

We don't have an identity. If the right hand side was -cos(x), instead of -sin(x), then we would have an identity.

7 0

3 years ago

Please help me with this

Alisiya [41]

Woahhhh lol one sec

8 0

3 years ago