(2-5i)(3+i)
use foil method to expand it into standard form
6+2i-15i+5i^2
5i^2-13i+6
Answer:
it's 3
Step-by-step explanation:
Number 3 is 3 units away from 0, and thus the absolute value of 3 is 3.
Answer:
Step-by-step explanation:
c(t)=40:0≤t≤400
=40+0.50 (t-400):t≥400
Note: √a * √a = a
√a * √b = √ab
(√2 + √10)² = (√2 + √10)(√2 + √10)
= √2(√2 + √10) + √10(√2 + √10)
= √2*√2 + √2*√10 + √10*√2 + √10*√10
= 2 + √20 + √20 + 10
= (2 + 10) + (√20 + √20)
= 12 + 2√20
√20 = √(4 *5) = √4 * √5 = 2√5
= 12 + 2√20 = 12 + 2(2√5)
= 12 + 4√5
Answer: -2.1p + 1.7
2.4 - 6p - 0.7 + 3.9p
Subtract 6p from 3.9p. (-2.1p)
Subtract 0.7 from 2.4. (1.7)
