For this case we have a function of the form 
, where
To find the real zeros we must equal zero and clear the variable "x".
We add 10 to both sides of the equation
We apply cube root to both sides of the equation:
![\sqrt[3]{(x-12)^3} = \sqrt[3] {10}\\x-12 = \sqrt[3] {10}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%28x-12%29%5E3%7D%20%3D%20%5Csqrt%5B3%5D%20%7B10%7D%5C%5Cx-12%20%3D%20%5Csqrt%5B3%5D%20%7B10%7D)
We add 12 to both sides of the equation:
![x-12 + 12 = \sqrt[3] {10} +12\\x = \sqrt[3] {10} +12](https://tex.z-dn.net/?f=x-12%20%2B%2012%20%3D%20%5Csqrt%5B3%5D%20%7B10%7D%20%2B12%5C%5Cx%20%3D%20%5Csqrt%5B3%5D%20%7B10%7D%20%2B12)
Answer:
Option D
<h3>
Answer: 15</h3>
=========================================================
Explanation:
n = number of new flash cards practiced
2n = number of old flash cards practiced
The 2n is due to the fact that the number of old flash cards is double that of the new ones (eg: 10 is twice that of 5).
The two expressions must add to 45.
new + old = total
n + 2n = 45
3n = 45
n = 45/3
n = 15
2n = 2*15 = 30
Noah practiced 15 new flash cards and 30 old flashcards which is a total of 15+30 = 45. This confirms our answer.
Also note that the ratio of new to old is 15:30 which reduces to 1:2, then we can multiply both sides by 5 to get 5:10. This effectively shows that 15:30 and 5:10 are the same equivalent ratio (just in different forms). This helps confirm our answer.
Answer:
4 1/3
Step-by-step explanation:
Basically, 27.7% of 970 is 268.69 grams, if 13 minutes so i’m pretty sure it’s 268.69 X 13 = 3492.97, it cannot be deduced from 970 unless it became −2522.97, is that the answer ur looking for?
2x^2-11x+12=0
Slip and slide
x^2-11x+24=0
(x-8)(x-3)
(x-8/2)(x-3/2)
(x-4)(2x-3)
Use ZPP
x-4=0
x=4
2x-3=0
2x=3
x=3/2
Final answer: x=3/2, x= 4
