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Pavlova-9 [17]
3 years ago
13

During the last central high school basketball game, the starting five players scored 11, 7, 21, 14, and 7 points, respectively.

for this distribution of scores, the range is
Mathematics
1 answer:
neonofarm [45]3 years ago
7 0
The range is defined as the difference between the highest and lowest values.

21 is the highest, 7 is the lowest
21-7=14

The range is 14. 

Hope this helps! A thanks/brainiest answer would be appreciated :)
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Answer:

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Step-by-step explanation:

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charle [14.2K]

Answer:

ME = 1.761* \frac{5}{\sqrt{15}}=2.273

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X= 75 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=5 represent the sample standard deviation

n=15 represent the sample size  

Solution to the problem

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=15-1=14

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,14)".And we see that t_{\alpha/2}=1.761

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    

And if we replace the values we got:

ME = 1.761* \frac{5}{\sqrt{15}}=2.273

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