3 years ago

-2x+y=-8 and 4x-6y=-24 I need help :(

Mathematics

1 answer:

Varvara68 [4.7K]3 years ago

3 0

Answer: <u>2x+y=-8</u> = <u>x=-1/2y-4 </u>

Step-by-step explanation:

2x+y=-8 -- Step 1: Add -y to both sides.

2x+y+−y=−8+−y

2x=−y−8

Step 2: Divide both sides by 2.

2x/2=-y-8/2

<h3 />

4x-6y=-24 -- Step 1: Add 6y to both sides.

4x−6y+6y=−24+6y

4x=6y−24

Step 2: Divide both sides by 4.

4x/4=6y-24/4

<h3>brainliest would be appreciated</h3>

You might be interested in

Division problem help pls

zepelin [54]

Answer: B. D. E. F.

Step-by-step explanation:

5 0

3 years ago

85,86,89,35,60,57,89,75,65

Marysya12 [62]

Answer:

sorry but what we have to do in this question

5 0

3 years ago

Jane works at a jewelry store and receives a 35% commission for everything she sells. Her sales this week were $5,500. How much

tresset_1 [31]

Step-by-step explanation:

5500×35=192500

/100=1925 $

6 0

3 years ago

Show that if A is invertible, then det Upper A Superscript negative 1det A−1equals=StartFraction 1 Over det Upper A EndFraction

netineya [11]

Answer:

Therefore

$det(A)*det(A^{-1}) = 1$ and $det(A^{-1}) = 1/det(A)$

Step-by-step explanation:

Remember that if

$I$ = Identity Matrix

then $det(I)=1$ .

Also remember that for any invertible matrix

$A*A^{-1} = I =$ Identity Matrix.

Therefore

$det(A*A^{-1}) = det(A)*det(A^{-1}) = det(I) = 1$

Therefore

$det(A)*det(A^{-1}) = 1$ and $det(A^{-1}) = 1/det(A)$

7 0

3 years ago

Write y=1/6x+7 in standard form using intergers.

Anna71 [15]

Answer:

–x + 6y = 42

Hope this answer is right!

4 0

3 years ago