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3 years ago

What is the diameter?

Mathematics

2 answers:

Finger [1]3 years ago

6 0

Answer:

The diameter is the length of the line through the center that touches two points on the edge of the circle.

Step-by-step explanation:

Cloud [144]3 years ago

5 0

Answer: It would be 25.4 with the pi symbol or 25.42 with 3.14

Step-by-step explanation:

You might be interested in

What are the zeroes of P(x) = x3 – 6x2 - x +62

Maurinko [17]

Answer:

x = 6

x = -1

x = 1

Step-by-step explanation:

Given:

Correct equation;

P(x) = x³ - 6x² - x + 6

Computation:

x³ - 6x² - x + 6

x²(x-6)-1(x-6)

(x-6)(x²-1)

we know that;

a²-b² = (a+b)(a-b)

So,

(x-6)(x²-1)

(x-6)(x+1)(x-1)

So,

zeroes are;

x = 6

x = -1

x = 1

4 0

3 years ago

A recipe to make 5 cupcakes calls for 10 tablespoons

arlik [135]

Answer:

10×5

Step-by-step explanation:

put a zero at the end of five and make it 50

3 0

3 years ago

There is 3 4 of an apple pie left from dinner. Tomorrow, Victor plans to eat 1 4 of the pie that was left. Enter how much of the

lora16 [44]

Answer:

3/16

Step-by-step explanation:

Let the size of the whole apple be T

Given that 3/4 of the apple is left, it means the size left

= 3T/4

Since Victor plans to eat 1/4 of the pie that was left, this amounts to

1/4 * 3T/4

= 3T/16

This means that Victor will eat 3/16 of the whole pie tomorrow

5 0

3 years ago

Can you double a square with a straightedge and a compass?

sergejj [24]

I'd say yes. If you use the diagonal as a reference. Take the square and set your compass to the width of the diameter of the square. Now put it on the page and mark a point. Put the point of the compass on that mark and make another mark. Now you can connect the two marks with the straight edge and you have a line that, if you made a square with sides that long, it'd have 2x the area of the first one. That's because the diagonal is the square root of 2 larger than one side. Square the square root of 2 and you've got 2. You lust need to make a perpendicular line to the first one to get the box going.

8 0

3 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

3 years ago

What is the diameter?​

What is the diameter?