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JulsSmile [24]
3 years ago
9

Help me pls on these

Mathematics
1 answer:
labwork [276]3 years ago
7 0

Answer:

first one is A) 21

second one is D) 150

Step-by-step explanation:

first one : add all marbles  =  10

there are 3 red

chances of picking a red 3/10 or 30 percent or .3

multiple 70 by .3 and get 21

second one:

A = 6a^{2} (Surface area of cube)

600 = 6a^{2}

a = 10

half of 10 is 5

6(5^{2}) = 150

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A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.
pav-90 [236]

Answer:

n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159

So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=2.25 represent the population standard deviation

n represent the sample size  

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159

So the answer for this case would be n=159 rounded up to the nearest integer

3 0
3 years ago
Whats the scale factor brainist
OleMash [197]

Answer:

?

Step-by-step explanation:

there is no scale factor (nothing to use)

thanks for the points though

have a blessed day :^)

3 0
3 years ago
Help..please i dont understand this assignment
FrozenT [24]

Answer

the second one, and 5th one

Step-by-step explanation:

because it is liquid

6 0
2 years ago
Read 2 more answers
Pls tell me it’s a,b,c,or d.Really need it thx
Serggg [28]

Answer: B and C are both correct so idk

Step-by-step explanation:

when you multiply the numbers outside of the choices, both answers in B and C are correct.

5 0
3 years ago
Solve for x: (3x-2)(x+1)=18x+4
Serga [27]
Answer: x= 7.752
explanation:
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2 years ago
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