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JulsSmile [24]
2 years ago
9

Help me pls on these

Mathematics
1 answer:
labwork [276]2 years ago
7 0

Answer:

first one is A) 21

second one is D) 150

Step-by-step explanation:

first one : add all marbles  =  10

there are 3 red

chances of picking a red 3/10 or 30 percent or .3

multiple 70 by .3 and get 21

second one:

A = 6a^{2} (Surface area of cube)

600 = 6a^{2}

a = 10

half of 10 is 5

6(5^{2}) = 150

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The scale of a map is 1 in. = mi. Find each length on the map
WITCHER [35]

The question gives the relationship to be

1in=21mi

We will interpolate to solve the question.

First Question: 147 mi

\begin{gathered} \text{If 1 in = 21 mi} \\ x\text{ in = 147 mi} \end{gathered}

Cross multiplying,

undefined

7 0
1 year ago
Three times the sum of a number and five is thrity-six? What is the number
andrew11 [14]
The number is 12.

7 + 5 = 12

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Hope I helped!
5 0
2 years ago
What is the area of this triangle
svet-max [94.6K]

Answer:

14

Step-by-step explanation:

7*4*1/2=14

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2 years ago
Find the product of 30−−√ and 610−−√. Express it in standard form (i.E., ab√).
Zina [86]

we are given

\sqrt{30} *\sqrt{610}

we can radical formula

\sqrt{a} *\sqrt{b}=\sqrt{a*b}

we get

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\sqrt{30} *\sqrt{610}=\sqrt{3*61*100}

we can  also write as

\sqrt{30} *\sqrt{610}=\sqrt{100}*\sqrt{3*61}

\sqrt{30} *\sqrt{610}=10\sqrt{183}............Answer


7 0
3 years ago
Read 2 more answers
A class of 32 students is organised in 33 teams every team consists of 3 students and there are no identical teams . show that t
Tresset [83]

Answer:

Step-by-step explanation:

Let's start by making up as many teams as we can with the 32 student. Given that each team is different, we can make 10 teams of 3 each. (we still have 23 more teams to make).

The last two people make a team of only 2. No matter which student from the 30 other students is picked, the team of two and the one the student is coming from will have one student in common. Though there are more borrowings that take place (many more), the results remain as stated. At least 2 teams will have 1 person in common.

The method is called the pigeon hole method.

6 0
3 years ago
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