Question

URGENT PLEASE ANSWER ASAP!!!!!!!!!!!

Answer 1

Answer: The gravity's constant value is $9.8 m/sec^2$.

Explanation:

The given function shows the distance from the ground (in meters) at time t (in sec).

$d(t)=-4.9t^2+50$

First derivative of displacement is velocity and the second derivative of displacement is acceleration.

Differentiate the given equation with respect to t.

$v(t)=d'(t)=-9.8t+0$

Differentiate the above equation with respect to t.

$a(t)=v'(t)=d''(t)=-9.8$

It is given that gravity is the only acceleration affecting the object and the negative sign shows the downward direction of the object.

Therefore, the gravity's constant value is $9.8 m/sec^2$.