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4 years ago

2+ | -1 | does this show the distance of 3?

Mathematics

2 answers:

GrogVix [38]4 years ago

8 0

Answer:

Correct

Step-by-step explanation:

"|" means absolute values. In other words, it changes any number to a positive one.

2 + |-1|

2 + 1

Best of Luck!

Alex787 [66]4 years ago

8 0

Yes because anything inside those lines is always positive

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If F(x)=4x-1 and g(x)=x^2+7, what is g(f(x))

VashaNatasha [74]

Answer

$g(f(x)) = = 16 {x}^{2} - 8x + 8$

step by step Explanation

The functions given are

$f (x)= 4x- 1$

$g(x)= {x}^{2} + 7$

We want to find:

$g(f (x))= g( 4x- 1)$

This implies that

$g(f (x))= ( (4x- 1)^{2} + 7)$

Let us now simplify

$( {a - b)}^{2} = {a}^{2} -2ab + {b}^{2}$

This implies that

$( (4x- 1)^{2} + 7) =( {(4x)}^{2} - 2(4x) \times 1 + 1$

Combine the terms to get,

$= 16 {x}^{2} - 8x + 1 + 7$

$= 16 {x}^{2} - 8x + 8$

6 0

4 years ago

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What’s the slope of the parallel line that passes through (-19, 14) and (19, 11).

laiz [17]

Answer:

19,12

Step-by-step explanation:

6 0

3 years ago

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

7 0

3 years ago

The perimeter of a rectangle is 20.2 CM and it's area is 24.4 cm squared what is its length and width

erma4kov [3.2K]

Answer:

Length of Rectangle = 4 cm And

Width of Rectangle = 1.9 cm

Step-by-step explanation:

Given as :

The perimeter of rectangle = 20.2 cm

The area of rectangle is 24.4 cm

Let the length be L

And width be w

Now Area of rectangle = Length × width

Or, 24.4 = L × W

And Perimeter = 2 (Length + Width ) = 2 (L + W )

Or, 20.2 = 2(L + W )

Or , L + W = 10.1 cm ............ 1

Now, (L - W )² = (L + W)² -4 LW

Or, (L - W )² = ( 10.1)² -4 (24.4)

I.e (L - W )² = 4.41

Or , L - W = 2.1 cm .............. 2

SO , From 1 and 2

( L + W) + (L - W) = 10.1 cm - 2.1 cm

Or, 2L = 8

∴ Length = 4 cm

Again , Width = 4 cm - 2.1 cm = 1.9 cm

Hence Length of Rectangle = 4 cm And

Width of Rectangle = 1.9 cm Answer

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3 years ago

What is StartFraction negative 23 over 6 EndFraction minus StartFraction 7 over 3 EndFraction

creativ13 [48]

Answer: $\frac{16}{3}$

Step-by-step explanation:

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4 years ago

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