Yes because they are constant throughout the table.
<u>Answer-</u>
<em>The polynomial function is,</em>

<u>Solution-</u>
The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1
The general form of the equation will be,
( ∵ (3-i) is the conjugate of (3+i) )








Therefore, this is the required polynomial function.
We solve for the diameters of radius of the given circles by using the equation,
C = πD
or C = 2πr
where D and r are diameter and radius, respectively.
Solving,
C = 34.54 units
D = C/π = 34.54 units / 3.14 = 11 units
r = C / 2π = 34.54 units/2(3.14) = 5.5 units
C = 59.66 units
D = C/π = 59.66 units/3.14 = 19 units
r = D2 = 9.5 units
C = 23.236 units
D = 23.236 units/3.14 = 7.4 units
r = D/2 = 3.7 units
C = 23.376 units
D = 23.376 units / 3.14 = 7.4 units
r = D/2 = 3.7 units
C = 13.188 units
D = 13.188 units/3.14 = 4.2 units
r = D/2 = 2.1 units