A metallurgist has one alloy containing 26% copper and another containing 69% copper. How many pounds of each alloy must he use

Question

1 year ago

8

to make 53 pounds of a third alloy containing 50% copper?

1 answer:

zaharov [31] · Answer 1 · 2023-09-06T01:48:30+03:00

The pounds of alloy that contains 26% copper that would be used is 23.42 pounds.

The pounds of alloy that contains 69% copper that would be used is 29.58 pounds.

<h3>What are the linear equations that represent the question</h3>

0.26a + 0.69b = (53 x 0.5)

0.26a + 0.69b = 26.50 equation 1

a + b = 53 equation 2

Where:

<h3>How many pounds of each alloy should be in the third alloy?</h3>

Multiply equation 2 by 0.26

0.26a + 0.26b = 13.78 equation 3

Subtract equation 3 from equation 2

12.72 = 0.43b

b = 12.72 / 0.43

b = 29.58 pounds

a = 53 - 29.58 = 23.42 pounds

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