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kenny6666 [7]
4 years ago
13

Help me with the question in the picture?

Mathematics
1 answer:
velikii [3]4 years ago
6 0

Answer: -3< 0


Step-by-step explanation: this means -3 is less than 0.

As on number line -3 and 0 are marked. We know 0 is origin if we go rightward i .e towards the positive number all numbers are greater than zero.

But if we move leftward on number line the numbers are less than zero.


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Hii can someone explain to me how to do this? tyvm
Snezhnost [94]

Step-by-step explanation:

it's late but I hope it helps :)

imagine that the > symbol is just an equal sign

so for example

x+2>4

will look like

x+2=4

and you solve normally

×=2

now we bring the symbol back

x>2

but if you multiple or divide by a negative the sign flips

so say you have

-2x>4

make it into

-2x=4

solve

x=-2

but instead of >

you put

x < -2

5 0
3 years ago
In the function, 9 (2-) = 9 - 5x, what is the value of g (3)?
vekshin1

Answer: 53

Step-by-step explanation:

3 0
3 years ago
Convert into decimals (use your calculator): a) 6/38 b) 45/55 c) 4/28 d) 35/28 e) 1030/2030
Delicious77 [7]

Answer:

a.\hspace{3} \frac{6}{38} = 0.15789474\\\\b.\hspace{3} \frac{45}{55} = 0.81818181\\\\c.\hspace{3} \frac{4}{28} = 0.14285714\\\\d.\hspace{3} \frac{35}{28} = 1.25\\\\e.\hspace{3} \frac{1030}{2030} = 0.50738916

Step-by-step explanation:

Rational numbers, expressed as decimal numbers, are obtained from the operation of division between the integer of the numerator and the integer of the denominator. Then:

a.\hspace{3} \frac{6}{38} = 6\div38 = 0.15789474\\\\ b.\hspace{3} \frac{45}{55} = 45\div55 = 0.81818181\\\\c.\hspace{3} \frac{4}{28} = 4\div28 = 0.14285714\\\\ d.\hspace{3} \frac{35}{28} = 35\div28 = 1.25\\\\ e.\hspace{3} \frac{1030}{2030} = 1030\div2030 = 0.50738916

3 0
4 years ago
Analyze Ben’s work. Did he simplify the expression correctly? If not, what was his mistake?
Klio2033 [76]

Answer: No, he needed to apply the exponent to all factors in the product in the second step.

5 0
3 years ago
Read 2 more answers
Let f(x) = e ^3x/5x − 2. Find f'(0).
Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

Our friend asking what the actual function is has a point. I completed this under the assumption that what we have is:

f(x)=\frac{e^{3x}}{5x-2} and used the quotient rule to find the derivative, as follows:

f'(x)=\frac{e^{3x}(5)-[(5x-2)(3e^{3x})]}{(5x-2)^2} and simplifying a bit:

f'(x)=\frac{5e^{3x}-[15xe^{3x}-6e^{3x}]}{(5x-2)^2}and a bit more to:

f'(x)=\frac{5e^{3x}-15xe^{3x}+6e^{3x}}{(5x-2)^2} and combining like terms:

f'(x)=\frac{11e^{3x}-15xe^{3x}}{(5x-2)^2} and factor out the GFC in the numerator to get:

f'(x)=\frac{e^{3x}(11-15x)}{(5x-2)^2}  That's the derivative simplified. If we want f'(0), we sub in 0's for the x's in there and get the value of the derivative at x = 0:

f'(0)=\frac{e^0(11-15(0))}{(5(0)-2)^2} which simplifies to

f'(0)=\frac{11}{4} which translates to

The slope of the function is 11/4 at the point (0, -1/2)

4 0
3 years ago
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