Step-by-step explanation:
it's late but I hope it helps :)
imagine that the > symbol is just an equal sign
so for example
x+2>4
will look like
x+2=4
and you solve normally
×=2
now we bring the symbol back
x>2
but if you multiple or divide by a negative the sign flips
so say you have
-2x>4
make it into
-2x=4
solve
x=-2
but instead of >
you put
x < -2
Answer: 53
Step-by-step explanation:
Answer:
Step-by-step explanation:
Rational numbers, expressed as decimal numbers, are obtained from the operation of division between the integer of the numerator and the integer of the denominator. Then:
Answer: No, he needed to apply the exponent to all factors in the product in the second step.
Answer:
Step-by-step explanation:
Our friend asking what the actual function is has a point. I completed this under the assumption that what we have is:
and used the quotient rule to find the derivative, as follows:
![f'(x)=\frac{e^{3x}(5)-[(5x-2)(3e^{3x})]}{(5x-2)^2}](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Cfrac%7Be%5E%7B3x%7D%285%29-%5B%285x-2%29%283e%5E%7B3x%7D%29%5D%7D%7B%285x-2%29%5E2%7D)
and simplifying a bit:
![f'(x)=\frac{5e^{3x}-[15xe^{3x}-6e^{3x}]}{(5x-2)^2}](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Cfrac%7B5e%5E%7B3x%7D-%5B15xe%5E%7B3x%7D-6e%5E%7B3x%7D%5D%7D%7B%285x-2%29%5E2%7D)
and a bit more to:
and combining like terms:
and factor out the GFC in the numerator to get:
That's the derivative simplified. If we want f'(0), we sub in 0's for the x's in there and get the value of the derivative at x = 0:
which simplifies to
which translates to
The slope of the function is 11/4 at the point (0, -1/2)
