Answer:
IQ scores of at least 130.81 are identified with the upper 2%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 100 and a standard deviation of 15.
This means that 
What IQ score is identified with the upper 2%?
IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.




IQ scores of at least 130.81 are identified with the upper 2%.
This will help a lot if you go to desmos! Just graph the equation on there! It’s much easier to see on computer
Answer:
(s-20)(s+3)
Step-by-step explanation:
(s-5)(s-12) equals s²-17x+60 and is incorrect
Answer:Piqued the same time.you should come over to the same time as before I have to take the
Step-by-step explanation:
I ooo
The answer to this is c. y=2x-6