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Marina86 [1]
3 years ago
5

Answer to 4(x-3)+5x-^2 for x=2

Mathematics
1 answer:
Ulleksa [173]3 years ago
7 0

Answer:

Given expression 4(x-3)+5x^{\bf -2} for x=2  is

4(x-3)+5x^{\bf -2}=-\frac{\bf 11}{\bf 4}

Step-by-step explanation:

Given expression is  4(x-3)+5x^{-2} for x=2

Let f(x) be the given expression

f(x)=4(x-3)+5x^{-2}

now to find f(x) for x=2

ie., put x=2 in f(x) we get

4(x-3)+5x^{-2}=4(2-3)+5(2)^{-2}

4(x-3)+5x^{-2}=4(-1)+5(2)^{-2}

4(x-3)+5x^{-2}=-4+5\times \frac{1}{2}^}2}

4(x-3)+5x^{-2}=-4+5\times \frac{1}{4}

4(x-3)+5x^{-2}=-4+ \frac{5}{4}

4(x-3)+5x^{-2}= \frac{-16+5}{4}

4(x-3)+5x^{-2}= \frac{-11}{4}

4(x-3)+5x^{-2}=-\frac{11}{4}

Therefore the given expression 4(x-3)+5x^{-2} for x=2  is

4(x-3)+5x^{-2}=-\frac{11}{4}

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