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Vera_Pavlovna [14]
3 years ago
15

Using the defects method, which of these relationships represents the Law of Cosines if the measure of the included angle betwee

n the sides a and b of ∆ABC is more than 90°?
A. area of square c2 = -area of square a2 – area of square b2 + area of defect1 + area of defect2

B. area of square c2 = area of square a2 + area of square b2 + area of defect1 – area of defect2

C. area of square c2 = area of square a2 + area of square b2 – area of defect1 – area of defect2

D. area of square c
Mathematics
2 answers:
KonstantinChe [14]3 years ago
7 0

PLATO the answer is D area of square c2 = area of square a2 + area of squareb2 + area of defect1+ area of defect2 I just did this question

Radda [10]3 years ago
3 0
Cosine Law:
c² = a² + b² - 2 a b cos C
Answer:
C ) area of square c² = area of square a² + area of square b²
- area of defect 1 - area of defect 2 
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Novosadov [1.4K]

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Hence the correct option is the last one . The triangle is an obtuse angled triangle.

Step-by-step explanation:

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ii) it is<em><u> not</u></em> a right angled triangle as \sqrt{9^{2} + 15^{2} } \neq  19 and \sqrt{9^{2} + 15^{2} } <  19

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The real solutions the equation as given in the task content; x² = 225 are; +25 and -25.

<h3>What are the real solutions of the equation as given in the task content?</h3>

It follows from the task content that the real solutions of the equation as given in the task content can be determined as follows;

x² = 225

x = ± 15

Therefore, the real solutions of the equation are; +25 and -25.

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