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BigorU [14]
3 years ago
5

Jeremy is buying a new bicycle. For the style he likes best, the bicycle shop sells 26-inch and 29-inch frames in blue, red, and

black. What is the probability that he selects a black 29-inch bicycle?
Mathematics
1 answer:
Leno4ka [110]3 years ago
8 0

Answer:

1 out of 6

Step-by-step explanation:

there are 6 different combinations

26in - blue

26in- red

26in- black

29in - blue

29in - red

29in - black

The probability then come out to 1 out of 6

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Will give brainiest if someone answers correctly<br><br> x=<br> Length=<br> Width=
Elena-2011 [213]

According to question,

= 8x² + 6x - 2 = 228

= 8x² + 6x - 230 = 0

= 2(4x² + 3x - 115) = 0

= 2(4x² + 23x - 20x - 115) =0

= 2(x(4x +23) -5(x - 23) )= 0

= 2((x-5)(4x+23)) = 0

x = 5 , x = -23/4

let x = 5

so length 4x - 1

= 4 × 5 - 1

= 19 ft

width = 2x + 2

= 2 × 5 + 2

= 22 ft

_______

gosh! finally did it.. was too big -_-

8 0
3 years ago
Two data sets have the same mean,
nirvana33 [79]

For Data Set B, we see that the data is more varied. The absolute deviations are 4, 3, 2, 5. The average of these absolute deviations is 3.5. MAD_B = (4+3+2+5)/4 =3.5 M ADB

Hence, The average of these absolute deviations is 3.5.

5 0
2 years ago
Can y'all please help.
sattari [20]

Answer:

See explanation

Step-by-step explanation:

<u>Step 1.</u> Substitute for d to solve for n:

From the first equation:

d=70-n

Then substitute it into the second equation:

0.1(70-n)+0.05n=5.5\\ \\7-0.1n+0.05n=5.5\\ \\7+(-0.05n)=5.5\\ \\-0.05n=5.5-7=-1.5\\ \\n=\dfrac{-1.5}{-0.05}=30

<u>Step 2:</u> Substitute for n to solve for d:

d+n=70\\ \\d+30=70\\ \\d=70-30=40

There are 40 dimes and 30 nikels in the piggy bank

6 0
4 years ago
Question 5 of 5 0 3 4 5 6 7 8 9 10 Which of the following could be the number shown on the number line? O A A. V20 OB. √24 C. 27
8_murik_8 [283]

Answer:

hi may u send a pic?

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
for the data values below construct a 95 confidence interval if the sample mean is known to be 12898 and the standard deviation
Volgvan

Answer:

A 95% confidence interval for the population mean is [3315.13, 22480.87] .

Step-by-step explanation:

We are given that for quality control purposes, we collect a sample of 200 items and find 24 defective items.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                             P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~  t_n_-_1

where, \bar X = sample proportion of defective items = 12,898

             s = sample standard deviation = 7,719

            n = sample size = 5

             \mu = population mean

<em> Here for constructing a 95% confidence interval we have used a One-sample t-test statistics as we don't know about population standard deviation. </em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ; </u>

P(-2.776 < t_4 < 2.776) = 0.95  {As the critical value of t at 4 degrees of

                                               freedom are -2.776 & 2.776 with P = 2.5%}  

P(-2.776 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.776) = 0.95

P( -2.776 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.776 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.776 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.776 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.776 \times {\frac{s}{\sqrt{n} } } , \bar X+2.776 \times {\frac{s}{\sqrt{n} } } ]

                                = [ 12,898-2.776 \times {\frac{7,719}{\sqrt{5} } } , 12,898+2.776 \times {\frac{7,719}{\sqrt{5} } } ]

                               = [3315.13, 22480.87]

Therefore, a 95% confidence interval for the population mean is [3315.13, 22480.87] .

5 0
4 years ago
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