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swat32
3 years ago
8

Buchanan corp. is refunding $10 million worth of 10% debt. the new bonds will be issued for 8%. The corporation's tax rate is 35

%. The call premium is 9% what is the net cost of the call premium after taxes?
Mathematics
1 answer:
Alik [6]3 years ago
5 0
The net cost of call premium can be calculated considering the total amount after taxes deductions times the percentage of the call premium.

Writing the percentage as a decimal number, we get:

10000000 × (1 - 0.35) × 0.09 = 585000

The <span>net cost of the call premium after taxes is 585000$.</span>

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If 72 is 120% of a number, what is 80%<br> of this number?
cupoosta [38]

Answer:

60

Step-by-step explanation:

As we have all the required values we need, Now we can put them in a simple mathematical formula as below:

STEP 172 = 120% × Y

STEP 272 =  

120

100

× Y

Multiplying both sides by 100 and dividing both sides of the equation by 120 we will arrive at:

STEP 3Y = 72 ×  

100

120

STEP 4Y = 72 × 100 ÷ 120

STEP 5Y = 60

Finally, we have found the value of Y which is 60 and that is our answer.

You can easily calculate 72 is 120 percent of what number by using any regular calculator, simply enter 72 × 100 ÷ 120 and you will get your answer which is 60

7 0
3 years ago
What is the solution of the equation 14^x=5?<br> Round your answer to the nearest ten-thousandth.
deff fn [24]
Take ln to both sides
ln 14^x = ln 5
then you'll get
x ln 14 = ln 5
divide both sides by ln 14
x = 0.6098533345
after rounding
x = 0.6099
4 0
3 years ago
Read 2 more answers
You recently sent out a survey to determine if the percentage of adults who use social media has changed from 66%, which was the
il63 [147K]

Answer:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Of the 2809 people who responded to survey, 1634 stated that they currently use social media.

This means that n = 2809, \pi = \frac{1634}{2809} = 0.5817

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 - 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.56

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 + 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.6034

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

6 0
3 years ago
Please help it's urgent!Need help quick!
belka [17]

Answer:

Solution

Step-by-step explanation:

Hope this helped :)

5 0
3 years ago
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No need to show work only need answer thx!
Stella [2.4K]
X=-5, X=4 hope this helps
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3 years ago
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