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Simora [160]
3 years ago
10

How many tenths are there in 2.7?

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
8 0

Answer:

There are 7 tenths

Step-by-step explanation:

The tenths spot is the first spot over to the right of the decimal place, so there are 7 tenths

svetlana [45]3 years ago
3 0

Answer:

One,,,,,,,,,,,,,,,,,,,,,,

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Did u get the answers cuz I got the same question

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The angles listed from largest to smallest are __________________
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B, A, C

Step-by-step explanation:

That's a 30-60-90 triangle.

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Viktor earns $15.75 per hour cleaning pools. How much money will Viktor earn if he cleans 22 pools? Round your answer to the nea
Bingel [31]
$347

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4 0
3 years ago
LAW OF SINES??? NEED HELP.​
snow_tiger [21]

Answer:

Step-by-step explanation:

We know by the Triangle Angle-Sum Theorem that the angles of a triangle all add up to equal 180.  So we find angle B:

180 - 82 - 55 = 43

So angle B = 43.  Now we can use the Law of Sines to solve for side b:

\frac{sin(55)}{8}=\frac{sin(43)}{b}

Cross multiply to get

b sin(55) = 8 sin(43) and divide to solve for b:

b=\frac{8sin(43)}{sin(55)} so

b = 6.6605

3 0
4 years ago
An insurance company divides its policyholders into low-risk and high-risk classes. 60% were in the low-risk class and 40% in th
AleksAgata [21]

Answer:

a). 0.294

b) 0.11

Step-by-step explanation:

From the given information:

the probability of the low risk = 0.60

the probability of the high risk = 0.40

let C_o represent no claim

let C_1 represent 1 claim

let C_2 represent 2 claim :

For low risk;

so, C_o  = (0.80 * 0.60 = 0.48),  C_1 =  (0.15* 0.60=0.09),   C_2 = (0.05 *  0.60=0.03)

For high risk:

C_o  = (0.50 *  0.40 = 0.2),  C_1 =  (0.30 *  0.40 = 0.12) ,   C_2 = ( 0.20 *  0.40 = 0.08)

Therefore:

a),  the probability that a randomly selected policyholder is high-risk and filed no claims can be computed as:

P(H|C_o) = \dfrac{P(H \cap C_o)}{P(C_o)}

P(H|C_o) = \dfrac{(0.2)}{(0.48+0.2)}

P(H|C_o) = \dfrac{(0.2)}{(0.68)}

P(H|C_o) = 0.294

b) What is the probability that a randomly selected policyholder filed two claims?

the probability that a randomly selected policyholder be filled with two claims = 0.03 + 0.08

= 0.11

7 0
3 years ago
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