All categories

2 years ago

How many tenths are there in 2.7?

Mathematics

2 answers:

Novosadov [1.4K]2 years ago

8 0

Answer:

There are 7 tenths

Step-by-step explanation:

The tenths spot is the first spot over to the right of the decimal place, so there are 7 tenths

svetlana [45]2 years ago

3 0

Answer:

One,,,,,,,,,,,,,,,,,,,,,,

You might be interested in

The function y = f(x) is graphed below. What is the average rate of change of the

Serjik [45]

The average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.

<h3>What is the average rate of change?</h3>

The average Rate of Change of the function f(x) can be calculated as;

$f(x) = \dfrac{f(b) - f(a)}{b-a}$

Interval -3 ≤ x ≤-1

a = -3, b = -1

f(a) = f(-3) = -20

f(b) = f(-1) = 0

Step 2: Find Average

$f(x) = \dfrac{f(b) - f(a)}{b-a}\\\\\\f(x) = \dfrac{f(-1) - f(-3)}{-1-(-3)}\\\\\\f(x) = \dfrac{0 - (-20)}{2}\\\\f(x) = 10$

Therefore, the average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.

Learn more about average rate;

brainly.com/question/20784578

#SPJ1

3 0

1 year ago

Its due today pls help ASAP

Maksim231197 [3]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

1. The people of Whoville were shopping like crazy to get their lists completed! one customer bought a wreath for $12 and seven

OlgaM077 [116]

1 = 6
5=8
6=75%?
7=21?
8=21
9=400
10=100
11=40

These are all the one I got the ones with ? At the end I’m not sure about

4 0

3 years ago

PLEASE HELP I BEG CLICK ON THIS!! It’s not that hard<br> :(((( sorry if blurry

mash [69]

Answer:

b hope i helped you have a good day

8 0

3 years ago

Quadrant:

NISA [10]

<h2>✒️Area Between Curves</h2>

$\small\begin{array}{ |c|c} \hline \bold{Area\ Between\ Curves} \\ \\ \textsf{Solving for the intersection of }\rm y = x^2 + 2\textsf{ and }\\ \rm y = 4, \\ \\ \qquad \begin{aligned} \rm y_1 &=\rm y_2 \\ \rm x^2 + 2 &=\rm 4 \\ \rm x^2 &= \rm 2 \\ \rm x &=\rm \pm \sqrt{2} \end{aligned} \\ \\ \textsf{We only need the first quadrant area bounded} \\ \textsf{by the given curves so the integral for the area} \\ \textsf{would then be} \\ \\ \boldsymbol{\displaystyle \rm A = \int_{\ a}^{\ b} {\left( \begin{array}{c}\text{upper} \\ \text{function}\end{array} \right) - \left( \begin{array}{c} \text{lower} \\ \text{function} \end{array} \right)\ dx}} \\ \\ \displaystyle \rm A = \int_{0}^{\sqrt{2}} \Big[4 - (x^2 + 2)\Big]\ dx \\ \\ \displaystyle \rm A = \int_{0}^{\sqrt{2}} (2 - x^2)\ dx \\ \\ \rm A = \left[2x - \dfrac{x^3}{3}\right]_{0}^{\sqrt{2}} \\ \\ \rm A = 2\sqrt{2} - \dfrac{\big(\sqrt{2}\big)^3}{3} \\ \\ \rm A = 2\sqrt{2} - \dfrac{2\sqrt{2}}{3} \\ \\\red{\boxed{\begin{array}{c} \rm A = \dfrac{4\sqrt{2}}{3}\textsf{ sq. units} \\ \textsf{or} \\ \rm A \approx 1.8856\textsf{ sq. units} \end{array}}} \\\\\hline\end{array}$

#CarryOnLearning

#BrainlyForTrees

$\qquad\qquad\qquad\qquad\qquad\qquad\tt{Monday\:at \: 04-04-2022} \\ \qquad\qquad\qquad\qquad\qquad\qquad\tt{12:10 \: pm}$

5 0

2 years ago