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3 years ago

Can someone help me ASAP???

1 answer:

5 0

Answer: The last member has to finish 11 more laps to complete 50 total laps

Step-by-step explanation:

$\frac{4}{10}$ of 50 = 20

2nd swimmer 8

22% of 50 = + 11

39 laps

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50 - 39 = 11 laps  (4th and last swimmer)

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P.S. I think this answer is late now

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Given that 5x:9=8:3 Calculate the value of x Give your answer in its simplest form.

lbvjy [14]

Answer:

24/5

Step-by-step explanation:

5x : 9

(8 : 3)×3

5x : 9

24 : 9

5x = 24

x = 24/5 = 4/4/5

8 0

2 years ago

Read 2 more answers

****Brainliest to best answer!!*** Thank u to everyone who helps!

Dmitrij [34]

Answer:

Step-by-step explanation:

When you read the question it says that her average speed from the library to the gym is 15 mph less than her speed from her home to the library. So x - 15 is what describes that situation.

If it is A it cannot be anything else.

B is incorrect. x - 15 is not a time. It is a rate. It can be used to develop the amount of time, but by itself it is still A.

C is incorrect. Her average speed from her house to the library is x

D is incorrect. The distance is given as the same as from her home to the library as from the library to the gym. Both are 4

7 0

3 years ago

HELP ASAP WILL GIVE BRAINLY

Mila [183]

Answer:

1 and 2 are not polyhedrons, as a circle has infinite sides

1. cone, 1 vertex

2. sphere, nothing

3. pentagonal prism?

wait but can't every face be a base???

anyway 7 faces, 10 vertices

4. triangular prism

5 faces, 6 vertices

Step-by-step explanation:

8 0

3 years ago

Solve the equation 6x + 2x - 5= 19 x=? Simplify your answer

SSSSS [86.1K]

Answer:

x = 3

Step-by-step explanation:

6x + 2x - 5= 19

8X -5 = 19

8x = 24

x = 3

7 0

3 years ago

Find a common factor for 3y^3+2y^2 and 6y^4+4y^3

Anit [1.1K]

Answer:

$3y + 2$

Step-by-step explanation:

We want to find a common factor for

$3 {y}^{3} + 2 {y}^{2}$

and

$6 {y}^{4} + 4 {y}^{3}$

We factor each of them to get;

$3 {y}^{3} + 2 {y}^{2} = {y}^{2} (3y + 2)$

and

$6 {y}^{4} + 4 {y}^{3} = 2 {y}^{3} (3y + 2)$

We can observe now that;

The factor common to both expression is

$3y + 2$

7 0

3 years ago