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aleksklad [387]
3 years ago
14

Can someone help me ASAP???

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
5 0

Answer: The last member has to finish <u><em>11 more laps</em></u> to complete <u><em>50 total laps</em></u>

Step-by-step explanation:

\frac{4}{10} of 50 =         20

2nd swimmer    8

22% of 50 =<u>   + 11      </u>

                        39 laps

---------------------------------------------

50 - 39 =<em><u> 11 laps  </u></em><em> (4th and last swimmer)</em>

<em>---------------------------------------------</em>

<em>P.S. I think this answer is late now </em>

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select the correct answer consider these functions f(x)=3x-7 g(x)=X +1/x-1 what is the value of f(g(3))
Alexeev081 [22]

Answer:

Me and my massive brain, among other massive things of mine, believe it to be -1

Step-by-step explanation:

6 0
3 years ago
A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch
ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

P = a person passes the security system

H = a person is a security hazard

Given:

P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01

Then,

P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The value of P (P) is:

P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0
3 years ago
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Komok [63]

Answer:

2

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0 = (2x+1) (x-5)

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This checks for the first last and middle terms so we factored correctly

Then using the zero product property

2x+1 = 0 and x-5 =0

2x = -1    x=5

x = -1/2  and x=5

This function crosses the x axis 2 times

8 0
3 years ago
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katen-ka-za [31]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
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