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2 years ago

What is >>>>> -x<15-2x

Mathematics

1 answer:

Gemiola [76]2 years ago

7 0

$-x$

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How to describe an inequality in your own words

emmasim [6.3K]

An inequality: a number sentence with ≤, ≥, <, >, = or ≠
≤ means: "less than or equal to"
≥ means: "greater than or equal to"
< means: "less than"
> means: "greater than"
≠ means: "not equal to"
= means: "equals"

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2 years ago

Ummm, Is this right

Alexeev081 [22]

Answer:

$\huge\boxed{\sf 25\ ml}$

Step-by-step explanation:

Total amount of water = 500 ml

Mary drank = 400 ml

Left:

= 500 ml - 400 ml

= 100 ml

This was divided equally among 4 friends.

So,

Each friend got:

= 100 ml/4

= 25 ml

$\rule[225]{225}{2}$

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1 year ago

Read 2 more answers

a man covers a distance of 15kn, in 3 hours partly by walking and partly by running. if he walks at 3km/h and runs at 9km/h, fin

irinina [24]

Speed = distance/time
distance = speed * time

let x = time covered by running
15 = run distance + walk distance
15 = 9(x) + 3(3-x)
15 = 9x + 9 - 3x
15 - 9 = 6x
6 = 6x
x = 1 hour

Therefore:
Running distance = speed * time
RD = 9km/hr * 1 hr
RD = 9km

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2 years ago

Look at the translation of the shape. Describe the translation that moves EFGH to E'F'G'H'.

mel-nik [20]

Answer:

4 boxes left 3 boxes up.

Step-by-step explanation:

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1 year ago

Read 2 more answers

Olivia is doing her math homework. For each problem she uses 3/4 sheet of paper. How many sheets of paper will Olivia need to co

VARVARA [1.3K]

<h3>Answer:</h3>

$15$

<h3>Step-by-step explanation:</h3>

$1$ problem = $\frac{3}{4}$ a page

$20$ problems = __ pages

- First, we need to figure out what this problem is asking us. This problem is asking for how many pieces of paper we need to do $20$ math questions. Well, the first step is knowing how many pieces of paper are needed for a single question. Luckily the question tells us that we need $\frac{3}{4}$ a paper for $1$ problem. So I have shown above what we know, and what we need to know. How do we figure out how many pages are needed for $20$ math problems?

There are a couple ways to solve this problem:

Add $\frac{3}{4}$ to itself $20$ times to get our resultant.
Multiply $\frac{3}{4}$ by $20$ .

(I listed them in order of time it takes to solve; #1 will take the longest, and #2 the shortest)

I'll do both methods and you can decide which you are most comfortable with.

Addition Method:

If we need to do $20$ problems, and $1$ problem is $\frac{3}{4}$ a page, doing $20$ problems is the same as doing $\frac{3}{4}$ a page $20$ times, so let's do just that by adding $\frac{3}{4}$ to itself $20$ times.

Yep, that's going to be a lot of work, but I'll show that you can add $\frac{3}{4}$ to itself this many times and get the same answer as the $2$ step solution seen with multiplication. Here's my work.

Note: (in case you struggle with fractions) Fractions when added together do NOT have a change in denominator (bottom number), only the numerator (top number) is added. Treat this as the same thing as addition, but you've got a number on the bottom that we'll deal with later.

In this step, I'm taking every pair of $\frac{3}{4}$ s and adding them together.

$\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}+\frac{3}{4}\\\frac{6}{4}+\frac{6}{4}+\frac{6}{4}+\frac{6}{4}+\frac{6}{4}+\frac{6}{4}+\frac{6}{4}+\frac{6}{4}+\frac{6}{4}+\frac{6}{4}$

Now, I'm again going to add my pairs together. Using this method saves time adding long chains of numbers and keeps your work minimized.

$\frac{6}{4}+\frac{6}{4}+\frac{6}{4}+\frac{6}{4}+\frac{6}{4}+\frac{6}{4}+\frac{6}{4}+\frac{6}{4}+\frac{6}{4}+\frac{6}{4}\\\frac{12}{4}+\frac{12}{4}+\frac{12}{4}+\frac{12}{4}+\frac{12}{4}$

Note: at this point you can actually convert your fractions to the whole number $3$ . Four goes into twelve $3$ times, so you'll end up with a clean number as your answer without any difficult conversions. Not converting now won't change your end result if you chose not to, but it will make things easier.

$\frac{12}{4}+\frac{12}{4}+\frac{12}{4}+\frac{12}{4}+\frac{12}{4}\\\frac{24}{4}+\frac{24}{4}+\frac{12}{4}\\\frac{48}{4}+\frac{12}{4}\\\frac{60}{4}\\ 15$

$\frac{12}{4}+\frac{12}{4}+\frac{12}{4}+\frac{12}{4}+\frac{12}{4}\\3+3+3+3+3\\15$

Multiplication Method:

This method is much, much less time consuming compared to doing the addition, so I recommend using this method in most word problems like this one.

Note: (read if you're having trouble with multiplication.) We have $1$ problem, $\frac{3}{4}$ a paper, being done $20$ times, so we are taking the value $\frac{3}{4}$ and adding it to itself $20$ times; we are multiplying $\frac{3}{4}$ by $20$ . Adding a number to itself $n$ times and multiplying a certain number by the value $n$ holds no difference except in how it's written and how many steps we have to use to solve it.

$\frac{3}{4}$ × $20$

If you're used to seeing only whole numbers being multiplied, this may help you grasp it:

$\frac{3}{4}$ × $20$ ⇒ $\frac{3}{4}$ × $\frac{20}{1}$

Remember that not only are both the numerators and denominators being multiplied, but separately. Here's the multiplications I did for both top and bottom.

numorater: $3$ × $20=60$ (look up "long-multiplication if you are confused by this answer.)