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puteri [66]
3 years ago
10

Eve plays basketball. She makes 7 free throws for every 3 free throws that she misses. If she missed 27 free throws at

Mathematics
1 answer:
VikaD [51]3 years ago
7 0
Well if she missed 27, we would need to divide 27 by 3 which gives us 9, then we’d multiply 7 by nine and it’s 63. She made 63 free throws
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AleksandrR [38]

Answer:

115° and 245°

Step-by-step explanation:

Given

cos x = - 0.4226

Since cos x < 0 then x is an angle in the second / third quadrants, thus

x =  (0.4226) = 65° ← related acute angle , thus

x = 180° - 65° = 115° ← angle in second quadrant

x = 180° + 65° = 245° ← angle in third quadrant

6 0
3 years ago
Read 2 more answers
Anyone know the answer?
chubhunter [2.5K]

Here is the answer.

You just have to remember the given formula.

3 0
3 years ago
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When asked to rewrite the expression (x3 + 2x? – x)-(-x3 + 2x2 + 6), Denise made a mistake. She did not get the correct answer,
DanielleElmas [232]

Answer:

She rewrote the problem without parentheses: x3+ 2x2 - x + x3 – 2x2 +6

Step-by-step explanation:

It looks like she didn't fully distribute the -

(x3 + 2x2 - x)-(-x3 + 2x2 + 6) :Original

x3+ 2x2 - x + x3 – 2x2 +6 :Changed

~

(x3 + 2x2 - x)-(-x3 + 2x2 + 6)

x3 + 2x2 - x + x3 - 2x2 - 6

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I hope this helps ^-^

3 0
2 years ago
Which of the following conditions would guarantee that triangles are identical?
7nadin3 [17]

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Step-by-step explanation:

1) This would guarantee similarity, but not necessarily that they are identical.

2) The angle has to be included between the two sides, which is not specifed.

3) This would work (SSS congruence)

4) It is not specified if the side is opposite the corresponding angles.

4 0
2 years ago
Can someone help me with this it’s for science and it’s due tomorrow
8_murik_8 [283]

Answer:

Hoping someone else can answer with more confidence, but here's what I have:

on the left hand side:

upper is partial/penumbral lunar eclipse

lower is total solar eclipse

on the right hand side:

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middle is total solar eclipse

bottom is partial/penumbral lunar eclipse

Hope I helped at least a little

6 0
2 years ago
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