All categories

3 years ago

A collection of nickels and dimes is worth $6.10. There are 67 coins in all. How many nickels are there?

Mathematics

2 answers:

mote1985 [20]3 years ago

8 0

There are 12 and 50 dimes

Afina-wow [57]3 years ago

7 0

Joe is going to have 18 nickels!

You might be interested in

I will give brainliest to the first one that does it correctly

Effectus [21]

Answer:

180-138

=42, is the answer

8 0

3 years ago

On a test that has a normal distribution, a score of 60 falls two standard deviations above the mean, and a score of 42 falls on

Sergeu [11.5K]

Answer:

Step-by-step explanation:

Given that:

$A \ score \ of \ 60 \ falls \ two \ standard \ deviations \ above \ the \ mean \\ \\ A \ score \ of \ 42 \ falls \ one \ standard \ deviation \ below \ the \ m ean$

The interval for score = 60 - 42 = 18

If we divide it by the 3 standard deviations; the interval result into

= 18/3

= 6

So, the standard deviation is 6, and the mean = 42 + 6

= 48

7 0

3 years ago

Read 2 more answers

If the total perimeter of the trail is 231ft, what is the length of the cave? (2 points)

valentinak56 [21]

Answer: yes it is indeed your very smart

8 0

3 years ago

a) find center of mass of a solid of constant density bounded below by the paraboloid z=x^2+y^2 and above by the plane z=4.(b) F

slava [35]

Answer: x-bar = y-bar = 0 whereas z-bar = 8/3

M= (c^2)/8 which is intern equal to 2 $\sqrt{2}$

Step-by-step explanation:

Find the area, by setting the limits as

= $4\cdot \int _0^{\frac{\pi }{2}}\int _0^2\int _{r^2}^4\:rdzdrd\theta$

$=4\cdot \int _0^{\frac{\pi }{2}}\int _0^2r\cdot \:4-r^3drd\theta$

$=4\cdot \int _0^{\frac{\pi }{2}}4d\theta$

$=8\pi$

Therefore;

Mxy= $\int _0^{2\pi }\int _0^2\int _{r^2}^4\:zrdzdrd\theta$

z-bar = 8/3

M= 8 $\pi$ dividing it into two volume gives us = 4 $\pi$

means $4\pi =\int _0^{2\pi }\int _0^{\sqrt{c}}\int _r^c\:rdzdrd\theta$

$4\pi =\left(\pi c^2-2\pi \frac{c^{\frac{3}{2}}}{3}\right)$

c=2 $\sqrt{2}$

5 0

4 years ago

A rectangular garden's length is 5 feet longer than its width. If its perimeter can be represented using the function P(x) = 4x

lara31 [8.8K]

4x+10=38
4x=28
x=7
garden is ,7 by ,12

6 0

3 years ago