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RideAnS [48]
3 years ago
10

Please help, I don’t get it

Mathematics
1 answer:
KatRina [158]3 years ago
5 0

Answer:

What do not you understand?

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Julie has 30 pounds of chocolate that
Fudgin [204]

Answer:

30 boxes

Step-by-step explanation:

1 box = 1 pound

x = 30 pound

30 Cross multiplied with 1

= 1 *30 =30

therefore: Julie can fill 30 boxes

7 0
3 years ago
If f(x)=3x-1 and g(x)=x+5, find (f o g)(x) and (g o f)(x)<br><br> (f o g)(x)=<br><br> (g o f)(x)
Nuetrik [128]

Answer:

(f o g)(x)= 3x + 14

(g o f)(x) = 3x + 4

Step-by-step explanation:

(f o g)(x) = f(g(x)) = f(x + 5) = 3(x + 5) - 1 = 3x + 15 - 1 = 3x + 14

(g o f)(x) = g(f(x)) = g(3x - 1) = 3x - 1 + 5 = 3x + 4

3 0
2 years ago
This the questions that have me stuck​
IRINA_888 [86]
First a and then b.
4 0
3 years ago
A rectangular area is to be fenced in with 300 feet of chicken wire. find the maximum area that can be enclosed.
GarryVolchara [31]
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.

2(x+y) = 300
x+y = 150
y = 150-x

A=x(150-x) <--(substitution)

The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150

So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.

A=75(150-75)
A=75*75
A=5625

So the maximum area that can be enclosed is 5625 square feet.
6 0
3 years ago
hello this is 6th grade hw and can someone help me the area and perimeter for all of them and plz explain how you got them
Scilla [17]
Text me ----- [email protected]
4 0
3 years ago
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