Answer:
2196 fish
Step-by-step explanation:
Weight of fish that the killer whale might eat in a month (30 days) = 14,000 lb
Weight of the fish that killer whale might eat in a day = 
lb.
Average weight of the fish that killer whale eats = 3.4 oz
Since,
1 pound(lb) = 16 ounces(oz)
So,
Weight of the fish that killer whale might eat in a day in ounces(oz) = 
oz
Since, a certain fish weighs 3.4 oz, in order to find the number of fish that killer whale must eat, we must divide the total weight in ounces by 3.4 ounces.
So, the number of fish that killer whale would eat = 
fish
Thus, the killer whale needs to eat 2196 fish.
Answer:
d. 32.9
Step-by-step explanation:
To find c, we'll use the Law of Sines that says:
And we'll isolate a to get:
We first need to find A, which is easy. The sum of the interior angles of a triangle is 180 degrees... and we already have 2 of them, so:
A = 180 - 90 - 47.3 = 42.7
(converted 47°18' to 47.3)
Then we will plug-in the information we already have
So, let's round it to 32.9 to match the answer number D.
One leg is horizontal, on the line y=3. Another leg is vertical, on the line x=1. The point where these intersect, D(1, 3) is the vertex of a right angle. Any right triangle inscribed in a circle has its hypotenuse as the diameter of the circle.
Since the triangle is a right triangle, the circumcenter is the midpoint of the hypotenuse: ((8, 3) + (1, -5))/2 = (4.5, -1).
I believe that it will take one day
