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2 years ago

Alexandra has $15 to buy drinks for her friends at the baseball game. Soda

Mathematics

1 answer:

EleoNora [17]2 years ago

6 0

Answer:

Step-by-step explanation:

write an equation for the costs:

if x is the number of sodas

and y is the number of waters

2.75x + 2y <= 15

(<= is less than or equal to)

if we substitute 3 for y

we get 2.75x + 2(3) <= 15

2.75x + 6 <= 15

2.75x <= 9

9 / 2.75 = 3.2727

however, you cannot buy part of a soda

so, round to 3

you also cannot buy negative sodas

so, the answer is C

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Lena is converting 2/25 to a percent. What should she multiply the numerator and denominator of the fraction by to find the perc

NNADVOKAT [17]

A percent is a number out of 100, so you'd want to multiply the denominator to get 100. In this case, 25 would have to be multiplied by 4 to get 100. To keep the fractions equal to each other, you have to multiply the numerator by the same thing. 2*4=8. Therefore, your fraction would be 8/100 or 8%

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2 years ago

Read 2 more answers

Janine,who brought 15$ worth of make up, spent 6$ less than leah spent

Aneli [31]

Janine = J = 15
Leah = L = ?

L = J + 6
L = 15 + 6
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So Leah spent $21

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3 years ago

I need help i got confused after 3 of these

Nikolay [14]

-1, -1 I think is the answer

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2 years ago

It would be great if someone could help me with this problem

GaryK [48]

Y-intercept (0, 1)
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2 years ago

G a survey of property owners' opinions about a street-widening project was taken to determine if owners' opinions were related

Naily [24]

Answer:

The expected frequency for people against the project and who have over 120 feet of property foot frontage is 3.9.

Step-by-step explanation:

The data provided is:

Opinion

Front Footage For Undecided Against Total

Under 45 feet 12 4 4 20

45-120 feet 35 5 30 70

Over 120 feet 3 2 5 10

Total 50 11 39 100

The formula to compute the expected frequency is:

$E(X)=\frac{\text{Row Total}\times \text{Column Total}}{\text{TOTAL}}$

Compute the expected frequency for people against the project and who have over 120 feet of property foot frontage as follows:

$E(X)=\frac{\text{Row Total}\times \text{Column Total}}{\text{TOTAL}}$

$E(5)=\frac{10\times 39}{100}=\frac{39}{10}=3.9$

Thus, the expected frequency for people against the project and who have over 120 feet of property foot frontage is 3.9.

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2 years ago