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AnnyKZ [126]
4 years ago
6

F(x)=20(0.5)^x F(3)=

Mathematics
1 answer:
Paraphin [41]4 years ago
8 0
 i think its 5x2^-x+2. sorry if im wrong ! if you download photomath that helps you with and math problem you have !
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Plz help due tonight
Nonamiya [84]

Answer:

right angle triangle

Step-by-step explanation:

2x+3x-10+110-x

4x/4x =80/4x

x=20°

A=40°

B=50°

C=90°

5 0
3 years ago
Read 2 more answers
Identify the graph of x^2-8y=0 for theta=90º and write and equation of the translated or rotated graph in general form.
vredina [299]

Answer:

The answer is parabola; (y')² - 8x' = 0 ⇒ answer (b)

Step-by-step explanation:

* At first lets talk about the general form of the conic equation

- Ax² + Bxy + Cy²  + Dx + Ey + F = 0

∵ B² - 4AC < 0 , if a conic exists, it will be either a circle or an ellipse.

∵ B² - 4AC = 0 , if a conic exists, it will be a parabola.

∵ B² - 4AC > 0 , if a conic exists, it will be a hyperbola.

* Now we will study our equation:

* x² - 8y = 0

∵ A = 1 , B = 0 , C =

∴ B² - 4AC = (0)² - 4(1)(0) = 0

∵ B² - 4AC = 0

∴ it will be a parabola.

∵ Ф = 90°

* The point (x , Y) will be (x' , y')

∵ x = x'cosФ - y'sinФ and y = x'sinФ + y'cosФ

∵ cos(90) = 0 and sin(90) = 1

∴ x = -y' and y = x'

* lets substitute x and y in the first equation

∴ (-y')² - 8(x') = 0

∴ (y')² - 8x' = 0

* We notice that the x' took the place of y and y' took the place of x

∴ The parabola rotated around the origin by 90°

∴ The equation of the parabola is (y')² - 8x' = 0

* The answer is parabola, with angle of rotation 90°

* The equation is (y')² - 8x' = 0

* Look to the graph

- The blue is x² - 8y = 0

- The green is (y')² - 8x' = 0

7 0
4 years ago
Read 2 more answers
M&amp;M plain candies come in various colors. According to the M&amp;M/Mars Department of Consumer Affairs, the distribution of
lyudmila [28]

Answer:

A) 0.12. Yes. Choosing a green and blue M&M is possible

B) 0.43. Yes. Choosing a yellow and red M&M is possible

C) 0.78

Step-by-step explanation:

First of all, the summation of the distribution of all colours is;

Σ(all colors ) = 22% + 20% + 23% + 10% + 6% + 6% + 13% = 100%, or 1.

Thus;

a) P(green candy or blue candy) is;

P(GREEN ∪ BLUE) = P(G) + P(BL)

P(GREEN ∪ BLUE) = 6%+6%

P(GREEN ∪ BLUE) = 12% or 0.12

Now, due to the fact that we have to choose ONE candy and only ONE candy at random, then they are mutually exclusive: Yes. Choosing a green and blue M&M is possible

b)P(yellow candy or red candy is;

P(YELLOW ∪ RED) = P(Y) + P(R)

P(YELLOW ∪ RED) = 20% + 23% = 43% or 0.43

Yes. Choosing a yellow and red M&M is possible

c) P(NOT PURPLE)

the probability of having a purple is;

P(PURPLE) = 22% or 0.22

So, the Probability of NOT having a PURPLE is 1 - 0.22 = 0.78

4 0
3 years ago
M is the midpoint of CF for the point c(3, 4) and f (9, 8) find MG
luda_lava [24]
I don't know for sure but is it 6
3 0
3 years ago
Find Jacobs and Sarah's height in nanometers.
Elden [556K]
Sarahs is 
1.52 e+9
jacobs is
1.7 e+9
4 0
4 years ago
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