Answer:
(x + 3)^2 is left 3 because it becames 0 at -3
(x - 3)^2 is right 3 because it becames 0 at 3
x^2 +3 is up 3 because your just adding 3 units up
x^2 - 3 is down 3 because your just subtracting 3 units down
Step-by-step explanation:
Answer:
x=5
Step-by-step explanation:
Answer:
(a) yes
(b) no; see below
Step-by-step explanation:
(a) Integer roots of the quartic will be integer divisors of 6. One of the divisors of 6 is 3, so 3 is a possible root.
(b) In order for 3 to be a double root, it would have to be a double factor of 6. The only integer factors of 6 are 1, 2, 3, 6. (3² = 9 is not one.)
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The quartic can be written as ...
k(x -a)(x -b)(x -c)(x -d) . . . . . where a, b, c, d, k are integers
The constant term will be kabcd, of which each of the roots is a factor. If the constant is 6 and one root is d=3, then we must have
kabcd = 3kabc = 6
kabc = 6/3 = 2
Among these four integer factors, there must be an even number of minus signs, and one that has the value ±2. Another root whose value is 3 will not satisfy the requirements.
