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3 years ago

Helpp please!! Please simplify the problem and explain.

Mathematics

1 answer:

g100num [7]3 years ago

4 0

So I’m a 5th grader...but I wanted to see if I could help you so...this is how I did it.....first I started with the top, 6-2 which is 4 and then I did 4-4 which is 0 then the answer is....( put 2 on the bottom and 0 on the top. I hope I got it right ;(

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A man sold a small cottage at a loss of 5%.Had he sold it at a gain of 7%,he would have got Rs480 more.Find the cost price of th

NARA [144]

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Cost price of the cattage is Rs.6857.142857...

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1 year ago

An __________ is used to indicate the repeating part of a repeating decimal.

rusak2 [61]

Line above the repeating number

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3 years ago

A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet

Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

$L_{1} = 2W_{1}$

Also, the area of the walkway of 2 feet wide is 448:

$W_{2} = 2 ft$

$A_{T} = W_{2}*L_{2} = 448 ft^{2}$

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

$A_{T} = A_{1} + A_{w}$ (1)

The area of the pool is given by:

$A_{1} = L_{1}*W_{1}$

$A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}$ (2)

And the area of the walkway is:

$A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}$ (3)

Where the length of the bigger rectangle is related to the lower rectangle as follows:

$L_{2} = 4 + L_{1} = 4 + 2W_{1}$ (4)

By entering equations (4), (3), and (2) into equation (1) we have:

$A_{T} = A_{1} + A_{w}$

$A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}$

$448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}$

$224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}$

$224 = W_{1}^{2} + 8 + 6W_{1}$

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

$L_{1} = 2W_{1} = 2*12 ft = 24 ft$

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!

8 0

3 years ago

When given a quadratic equation, how do I graph it, and find the vertex?

NemiM [27]

So let’s say the equation is x^2 (x squared) -4x + 8 = 0. So you have to eventually graph a palabara. So to get the vertex, you have to find the line of symmetry (this plays a big part). So the formula for the line of symmetry is x= -b/2a. So A is this equation is 1. B is -4. C is 8. So you would plug these numbers in and you get 2. So (2,0) is your like of symmetry. Now you have to plug 2 back in for x. So when you do that you get 4 so the vertex is (2,4). So the vertex is (2, 4) and basically what the vertex is is it is the highest or lowest point of a palabara. So you can tel if it opens up or down by looking is A is negative or positive. If A is negative the it opens down. If it is positive then it opens up. So now you just put points in. Create a t chart. Like x/y. So when X is 1 for example, y is 5. So you graph (1, 5) and you graph the point that is the same distance from the line of symmetry. You do this until you have 5 points. I hope this helps. It’s hard to teach this over text.

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3 years ago

I need help with #17 some body pls help this is due in a few min and it’s my last question T^T

Ilia_Sergeevich [38]

Step-by-step explanation:

i think this would be the right answer...

6 0

3 years ago

Read 2 more answers