Question

Find two consecutive even integers such that the smaller added to three times the larger gives a sum of 54

Answer 1

Let n be the first even integer, and n+2 will be the second even integer. (Why? Think 2 and 4, 2+2=4. This is the case for every consecutive even integers).

n + 3(n+2) = 54
n + 3n + 6 = 54
4n = 48
n = 12, n+2 = 14

Answer 2

Let's call x  the smaller integer and x + 2 the larger one.

$x+3(x+2)=54$
$x + 3x + 6 = 54$
$4x = 48$
$x= \frac{48}{4}=12$

And $x+2=12+2=14$

Hope this helps !

Photon