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zmey [24]
3 years ago
14

Find two consecutive even integers such that the smaller added to three times the larger gives a sum of 54

Mathematics
2 answers:
REY [17]3 years ago
7 0
Let n be the first even integer, and n+2 will be the second even integer. (Why? Think 2 and 4, 2+2=4. This is the case for every consecutive even integers).

n + 3(n+2) = 54
n + 3n + 6 = 54
4n = 48
n = 12, n+2 = 14
sasho [114]3 years ago
3 0
Let's call x  the smaller integer and x + 2 the larger one.

x+3(x+2)=54
x + 3x + 6 = 54
4x = 48
x=  \frac{48}{4}=12

And x+2=12+2=14

Hope this helps !

Photon

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